Answer: The answers are
(i) The slope of segments DE and AC is not 0.
(ii) The coordinates of D and E were found using the Midpoint Formula.
Step-by-step explanation: We can easily see in the proof that the co-ordinates of D and E were found using the mid-point formula, not distance between two points formula. So, this is the first flaw in the Gina's proof.
Also, we see that the slope of line DE and AC, both are same, not equal to 0 but is equal to

which is 0 only if 
So, this is the second mistake.
Thus, the statements that corrects the flaw in Gina's proof are
(i) The slope of segments DE and AC is not 0.
(ii) The coordinates of D and E were found using the Midpoint Formula.
Answer:
I tried P as the Principle invested: 750, i, as the interest rate per compounding period = 8.2/100 = 0.082 n, number of compounding periods = 2, and t, time is 6 (6 months before July 1 from January 1?) Because I got 1931.03 and it's wrong:
Step-by-step explanation:
They are perpendicular to each other
Answer:
See explanation
Step-by-step explanation:
Q9. Statement Reason
1)
Given
2)
Given
3)
Reflexive property
4)
SAS postulate
5)
Corresponding parts of congruent triangles are congruent.
Q8. Statement Reason
1)
Given
2)
Alternate interior theorem
3)
Vertical angles theorem
4)
Given
5)
ASA postulate
Q7.
1)
- Given
- Given
Pairs of needed sides or pair of needed angles:

The postulate or theorem that can be used to prove the triangles are congruent:
SAS postulate
2)
- Given
- Given
Pairs of needed sides or pair of needed angles:

The postulate or theorem that can be used to prove the triangles are congruent:
SSS postulate
3)
- Given
- Given
Pairs of needed sides or pair of needed angles:

The postulate or theorem that can be used to prove the triangles are congruent:
ASA postulate
4)
- Given
- Given
Pairs of needed sides or pair of needed angles:

The postulate or theorem that can be used to prove the triangles are congruent:
AAS postulate
Q10. Statement Reason
1)
Given
2)
Given
3)
Reflexive property
4)
SAS postulate
Answer:
Dimensions of cabinet
x (wide) = 1.93 ft
y (hight) = 2.895 ft
p (depth) =0.43 ft
Step-by-step explanation:
Dimensions of cabinet
y height
x wide
p deph
From problem statement
y = 1.5 x V = y * x * p V = 1.5*x²p but p = V/y*x p = 2.4/1.5 x²
p = 1.6 / x²
Then
Area of top and bottom A₁ = 2*x*p ⇒ 2*x*1.6/x²
A₁ = 3.2 /x
And cost in $ C₁ = 0,9 * 3.2 /x ⇒ C₁ = 2.88/x
Area of sides (front and rear not included)
A₂ = 2*y *p A₂ = 3*x*1.6/x² A₂ = 4.8/x
And cost in $ C₂ = 0.9 * 4.8 /x C₂ = 4.32 /x
Area of front and rear A₃ =2* y*x A₃ = 2*1.5 *x² A₃ = 3x²
And cost C₃ = 0.3 * 3/x² = 0.9/x²
Total cost C(x) = C₁ + C₂ + C₃ C(x) = 2.88/x + 4.32/x + 0.9x²
Taking derivatives
C´(x) = -2.88/x² - 4.32 /x² + 0.9 x
C´(x) = 0 -2.88/x² - 4.32/x² + 0.9 x = 0 -2.88 - 4.32 + 0.9 x³ = 0
-7.2 + x³ = 0 x³ = 7.2
x = 1.93 ft y = 1.5*1.93 = 2.895 ft and p = 0.43 ft