3 years ago

One number is six times as large as another. The sum of their reciprocal is 7. What are the numbers

1 answer:

5 0

X=6y

sum of their reciprocals
(1/x)+(1/y)=7
x=6y
1/6y+1/y=7
1/6y+6/6y=7
7/6y=7
times both sides by 6y
7=42y
divide both sides by 42
1/6=y

x=6y
x=6(1/6)
x=6/6
x=1

the numbers are 1 and 1/6

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