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gavmur [86]
3 years ago
12

Which interval for the graphed function contains the local maximum?

Mathematics
1 answer:
Kamila [148]3 years ago
8 0

Answer:

B

Step-by-step explanation:

Definition: Suppose that f(x) is a function and D(f) is the domain of f(x). If a\in D(f), we say that f(a) is a Local Maximum on f(x) if f(a)\ge f(x) when x is near a. (See attached diagram for details)

From your graph you can see that the local maximum is nearly x=1.5, so interval [1,2] contains the local maximum.

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garik1379 [7]

(15a^4 - 30a^5 )/5a^2

= 5a^2(3a^2 - 6a^3) / 5a^2

= 3a^2 - 6a^3

or

= - 6a^3  +  3a^2

4 0
3 years ago
Find the approximate circumference of a circle with a diameter of 100 yards.
elixir [45]

Answer:

D. 314 yds

Step-by-step explanation:

Given:

Diameter = 100 yds

Required;

Circumference of the circle

Solution:

Circumference of circle = πd

Plug in the value

Circumference = π × 100

= 314 yds (nearest whole number)

5 0
3 years ago
Show that (1 + 2V3)2 = 13 +4V3
umka2103 [35]
Answer is 072 i think
7 0
3 years ago
HELP ME PLZZZ!!!! URGENT!!!​
finlep [7]

Answer:

Step-by-step explanation:

Given equation is,

x² + (p + 1)x = 5 - 2p

x² + (p + 1)x - (5 - 2p) = 0

x² + (p + 1)x + (2p - 5) = 0

Properties for the roots of a quadratic equation,

1). Quadratic equation will have two real roots, discriminant will be greater than zero. [(b² - 4ac) > 0]

2). If the equation has exactly one root, discriminant will be zero [(b² - 4ac) = 0]

3). If equation has imaginary roots, discriminant will be less than zero [(b² - 4ac) < 0].

Discriminant of the given equation = (p+1)^2-4(1)(2p-5)

For real roots,

(p+1)^2-4(1)(2p-5)>0

p² + 2p + 1 - 8p + 20 > 0

p² - 6p + 21 > 0

For all real values of 'p', given equation will be greater than zero.

5 0
3 years ago
If the integral of f(x)dx = 2.3 from 1 to 3 and F'(x) = f(x), what is the value of F(3) - F(0). The graph will be inserted as a
lana66690 [7]
<span>F(3)−F(0)=<span>∫30</span>f(x)dx</span><span>
so it looks like 2.3+1=3.3</span>
4 0
2 years ago
Read 2 more answers
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