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11 months ago

F(x) = 2-4 Find f(2)

Mathematics

1 answer:

Jet001 [13]11 months ago

8 0

Answer:

-8

Step-by-step explanation:

So first off, x is 2-4. So that's the default. It would be -2. If you multiply -2 by 2, it is -4.

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The endpoints of a side of rectangle ABCD in the coordinate plane are at A(1, 11) and B(6, 1). Find the equation of the line tha

babymother [125]

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2 years ago

!lol help pls im vv bad at math and angles

Vanyuwa [196]

Answer:

y=130°

Step-by-step explanation:

180-(90+40)

180-130

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3 years ago

The letters of the word COMBINE are placed at random in a row. In how many ways can an arrangement occur such that all vowels ar

Oksana_A [137]

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3 years ago

A company is producing two types of ski goggles. Thirty percent of the production is of type A, and the rest is of type B. Five

exis [7]

Answer:

$\dfrac{14}{29}$

Step-by-step explanation:

Let P(A) be the probability that goggle of type A is manufactured

P(B) be the probability that goggle of type B is manufactured

P(E) be the probability that a goggle is returned within 10 days of its purchase.

According to the question,

P(A) = 30%

P(B) = 70%

P(E/A) is the probability that a goggle is returned within 10 days of its purchase given that it was of type A.

P(E/B) is the probability that a goggle is returned within 10 days of its purchase given that it was of type B.

$P(A \cap E)$ will be the probability that a goggle is of type A and is returned within 10 days of its purchase.

$P(B \cap E)$ will be the probability that a goggle is of type B and is returned within 10 days of its purchase.

$P(E \cap A) = P(A) \times P(E/A)$

$P(E \cap A) = \dfrac{30}{100} \times \dfrac{5}{100}\\\Rightarrow P(E \cap A) = 1.5 \%$

$P(E \cap B) = P(B) \times P(E/B)$

$P(E \cap B) = \dfrac{70}{100} \times \dfrac{2}{100}\\\Rightarrow P(E \cap B) = 1.4 \%$

$P(E) = 1.5 \% + 1.4 \% \\P(E) = 2.9\%$

If a goggle is returned within 10 days of its purchase, probability that it was of type B:

$P(B/E) = \dfrac{P(E \cap B)}{P(E)}$

$\Rightarrow \dfrac{1.4 \%}{2.9\%}\\\Rightarrow \dfrac{14}{29}$

So, the required probability is $\dfrac{14}{29}.$

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3 years ago

If you toss 9 fair coins, in how many ways can you obtain at least one tail?

maks197457 [2]

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3 0

3 years ago