Answer:
d(4) = 64
Step-by-step explanation:
Using the recursive formula
d(n) = d(n - 1) + 17 with d(1) = 13, then
d(2) = d(1) + 17 = 13 + 17 = 30
d(3) = d(2) + 17 = 30 + 17 = 47
d(4) = d(3) + 17 = 47 + 17 = 64
Answer:
8
Step-by-step explanation:
use pythagoras theorem
a^2+b^2=c^2
a^2+6^2=10^2
a^2=10^2-6^2
a^2=100-36
a^2=64
a=square root of 64
a=8
<u>Answer:</u>
32 units
<u>Step-by-step explanation:</u>
We have a quadrilateral ABCD and we are given the following coordinates for these vertices:
A (-11,-6)
B (-3,0)
C (1,0)
D (1,-6)
AB = 
= 10 units
BC = 
= 4 units
CD = 
= 6 units
AD = 
= 12 units
Perimeter of ABCD = 
= 32 units
The slope is 1
The y-int is (0,-7)
