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d1i1m1o1n [39]
2 years ago
9

Simplify the expression

Mathematics
1 answer:
Nat2105 [25]2 years ago
7 0

Answer:

8x - 4y

Step-by-step explanation:

<u>First: </u><u>solve the parentheses</u>

8x - 7y - (3-6y)

<u>Second:</u><u> combine like terms (terms that both have y or x, or other variable)</u>

8x - 7y - (-3y)

<u>Third:</u><u> there are no more like terms, so you are left with this as your answer</u>

8x - 4y

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Pls help what is this as a simplified fraction (thank u Jesus loves u)
Arte-miy333 [17]

Answer:

7.9 or 79/10

Step-by-step explanation:

-12.166 / -1.54

12.166 / 1.54

7.9

4 0
3 years ago
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I need help with 6 <br><br><br> I’ll give brainliest
Katena32 [7]
If I understand it correctly then its complementary angle will be 115˚, because 180-65=115.
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3 years ago
Drag each tile to the correct cell in the table.
Gnoma [55]

Answer:

Ari has 14 pennies.

Step-by-step explanation:

                           Number             Value             Total value

Pennies                  p                      $0.01                  0.01p  

Nickels               (22 - p)                $0.05             $(22 - p)0.05  

Total                       22                        -                      $0.54

Since Ari has total value of the coins = $0.54

0.01p + (22 - p)0.05 = 0.54

0.01p - 0.05p + 1.1 = 0.54

-0.04p = -0.56

p = \frac{0.56}{0.04}

p = 14

Therefore, total number of pennies Ari has = 14

3 0
3 years ago
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Solve the following compound inequality.
Verdich [7]
The following compound? what’s the following compound
7 0
3 years ago
The sum of the first two terms of an infinite GP is 6 and each term is 5 times the sum of the succeeding termsthen the second te
kozerog [31]

Answer:

\dfrac{6}{7}.

Step-by-step explanation:

It is given that the sum of first two terms of an infinite GP is 6.

nth term of a GP is

a_n=ar^{n-1}

a+ar=6     ...(1)

Each term is 5 times the sum of the succeeding terms.

a_n=5(a_{n+1}+a_{n+2}+...+\infty)

ar^{n-1}=5(ar^n+ar^{n+1}+...+\infty)

ar^{n-1}=5ar^n(1+r+r^2+...+\infty)

Divide both sides by a.

r^{n-1}=5r^n(\dfrac{1}{1-r})    [\text{Sum of infinite GP}=\dfrac{a}{1-r}]

\dfrac{r^n}{r}=\dfrac{5r^n}{1-r}

\dfrac{1}{r}=\dfrac{5}{1-r}

1-r=5r

1=6r

\dfrac{1}{6}=r

The common ratio is 1/6.

Put r=1/6 in (1).

a+a(\dfrac{1}{6})=6

6a+a=36

7a=36

a=\dfrac{36}{7}

Second term ar=\dfrac{36}{7}\times \dfrac{1}{6}=\dfrac{6}{7}

Therefore, the second term is \dfrac{6}{7}.

4 0
3 years ago
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