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Ad libitum [116K]
3 years ago
5

3/20 4x + 2(x - 6) = 12

Mathematics
1 answer:
Nat2105 [25]3 years ago
7 0

Answer:

4x+2(x-6)=12

4x {}^{2}  - 24 + 2x - 12 = 12 \\ 4x {}^{2}   - 36 + 2x = 12 \\ 4x {}^{2}  + 2x = 12 + 36 \\ 4x {}^{2}  + 2x = 48 \\ 4x { }^{2}  + 2x - 48 = 0

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Find the area of the composite shape
Alexxandr [17]

Answer:

13.735 ft^{2}

Step-by-step explanation:

Area of a circle.

A=\pi r^{2}

r=d/2\\r=8/2\\r=4

A=\pi \times 4^{2}

A=16\pi

A \approx 50.2654824574

Area of a square.

A=s^{2}

A=8^{2}

A=64

Subtract the area of the square with the area of the circle.

64-50.2654824574

= 13.7345175426

I hope it helps.

Brainliest much appreciated.

8 0
3 years ago
How many groups of 3/4 are in 11/4
andrey2020 [161]

Answer:

3, with 2/4 left over

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Help please thank you!
irga5000 [103]

Answer:

Step-by-step explanation:

W(-4,-10) lies on third quadrant.

M(-12,0) lies on second quadrant or can say in x axis

C(8,3) lies on first quadrant.

K(11,-5) lies on fourth quadrant.

8 0
3 years ago
Please help me asap. I need an answer and full explanation. 1st person to complete that gets Brainliest. Question: Amelia likes
Zielflug [23.3K]

Answer:

22 cards

Step-by-step explanation:

Set up a ratio.

\frac{34}{29+x} =\frac{2}{3}

58+2x=102

2x=44

x=22

Check: Add 22 to 39. 22+29=51

34/51 = 2/3

Have a great day

3 0
3 years ago
A roast turkey is taken from an oven when its temperature has reached 185 degrees F and is placed on a table in a room where the
Vedmedyk [2.9K]
(a) Using Newton's Law of Cooling, \dfrac{dT}{dt} = k(T - T_s), we have \dfrac{dT}{dt} = k(T - 75) where T is temperature after T minutes.
Separate by dividing both sides by T - 75 to get \dfrac{dT}{T - 75} = k dt. Integrate both sides to get \ln|T - 75| = kt + C.

Since T(0) = 185, we solve for C:
|185 - 75| = k(0) + C\ \Rightarrow\ C = \ln 110
So we get \ln|T - 75| = kt + \ln 110. Use T(30) = 150 to solve for k:
\ln| 150 - 75 | = 30k + \ln 110\ \Rightarrow\ \ln 75 - \ln 110= 30k \Rightarrow \\ k= \frac{1}{30}\ln (75/110) = \frac{1}{30}\ln(15/22)

So

\ln|T - 75| = kt + \ln 110 \Rightarrow |T - 75| = e^{kt + \ln110} \Rightarrow \\ \\
|T - 75| = 110e^{kt} \Rightarrow T - 75 = \pm110e^{(1/30)\ln(15/22)t}  \Rightarrow \\
T = 75 \pm110e^{(1/30)\ln(15/22)t}

But choose Positive because T > 75. Temp of turkey can't go under.

T(t) = 75 + 110e^{(1/30)\ln(15/22)t} \\
T(45) = 75 + 110e^{(1/30)\ln(15/22)(45)}  = 136.929 \approx 137{}^{\circ}F

(b)

T(t) = 75 + 110e^{(1/30)\ln(15/22)t} = 75 + 110(15/22)^{t/30}  \\
100 = 75 + 110(15/22)^{t/30}   \\
25 = 110(15/22)^{t/30}  
\frac{25}{110} = (15/22)^{t/30}   \\
\ln(25/110) / ln(15/22) = t/30 \\
t = 30\ln(25/110) / ln(15/22)  \approx 116\ \mathrm{min}

Dogs of the AMS.
4 0
3 years ago
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