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1 year ago

Solve the literal eqaution |-ax-b|=c for x

Mathematics

1 answer:

Reptile [31]1 year ago

4 0

According to the given data we have the following equation:

|-ax-b|=c

So, to calculate the value of x we would have to apply the following property:

absolute rule

if |uI=a, a>o, then u=a or u=-a

Therefore, considering the propert above the calculation of would be as follows:

if a<0

-2x-1=-2

-2x=-1

x=1/2

if a>0

-2x-1=2

-2x=3

x=-3/2

The value of x would be 1/2 and -3/2

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Jason already knew 5 appetizer recipes before starting culinary school,and he will earn 1 new appetizer recipe during each week

djverab [1.8K]

Answer:

11 weeks

Step-by-step explanation:

16-5=11

Take away the five because he already new 5 recipes

11 ÷ 1 = 11

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3 years ago

Your school is choosing a new school mascot to represent all team sports. which group should you ask to get a random sample of s

ser-zykov [4K]

Answer: B. Every 10th students that enters the cafeteria

Explanation:

B is a random sample, while A, C, and D are biased.

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3 years ago

Find the area of the circle

andrezito [222]

Answer:

A=103.13cm

Step-by-step explanation:

Formula: A= c^2/4π (C being the circumference and ^2 means it's squared)

Plug in what you know: 36^2/4π

1296/4π= 103.13

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3 years ago

At Gallicum Enterprises, all employees are in one of three categories: J, K, or L. The ratio of the numbers of employees in J to

MrRa [10]

Answer:

380.

Step-by-step explanation:

Given:

Total number of employees at Gallicum Enterprises are in the ratio,

J : k : L = 1 : 3 : 5 for some time.

Last month, 20 new J employees were hired, and no employees left and the new ratio of J to K is now 1 : 2.

Question asked:

What is the new total number of employees at Gallicum Enterprises ?

Solution:

As given, J : K : L = 1 : 3 : 5 

So, J : K = 1 : 3

$\frac{J}{K} = \frac{1}{3} \ (1)$

As last month, 20 new J employees were hired, new ratio of J to K is now

1 : 2.

So, $\frac{J+20}{K}=\frac{1}{2} \ (2)$

Dividing equation 1 and 2,

$\frac{J}{K}\div{\frac{J+20}{K} } = \frac{1}{3}\div{\frac{1}{2} }$

$\frac{J}{K}\times{\frac{K}{J+20} } = \frac{1}{3}\times{\frac{2}{1} }\\\\ \frac{J}{J+20} =\frac{2}{3} \\\\$

By cross multiplication:

$3J=2(J+20)\\3J=2J+40$

Subtracting both sides by $2J$

$J=40$

From equation 1.

$\frac{J}{K} = \frac{1}{3} \\\\ \frac{40}{K} =\frac{1}{3} \\\\$

By cross multiplication:

$K=40\times3\\\\ K=120$

As given, J : K : L = 1 : 3 : 5

So, K : L = 3 : 5

$\frac{K}{L} =\frac{3}{5} \\\\\\ \frac{120}{L} =\frac{3}{5}$

By cross multiplication:

$120\times5=3\times L\\600=3L$

Dividing both sides by 3

$L =200$

New total number of employees after hiring 20 new J employees :

New J + K + L = (New J = J + 20 = 40 + 20 = 60 )

60 + 120 + 200 = 380

Therefore, the new total number of employees at Gallicum Enterprises is 380.

4 0

3 years ago

F(x) = 2x2. What is f(3)? Evaluate the function for the given input

schepotkina [342]

Answer:

f(3) = 12

Step-by-step explanation:

F(x) = 2x2. What is f(3)

f(3) = 2(3) 2

= 6x2

= 12

f(3) = 12

7 0

3 years ago