So hmmm let's see
she has a monthly income of 120 from investments, now, there are 12 months in a year, so her yearly income from investments are 120*12 or
$1440
she plays on a band, and makes 200 a week, now, there are 52 weeks in a year, so her yearly income from band playing is 200 * 52, or
$10400
her total annual income is 49696, now, if we subtract the band and investment income, we'd be left over with only what comes from her job payrate
so 49696 - 1440 - 10400 is 37856
so, she makes from her job, $37856 annually
now, she only works 28 hours weekly, how much is that yearly? well, 52 weeks in a year, she works 28*52 hours a year, let us divide 37856 by that
37856 ÷ ( 28 * 52) well, it ends up as 26
so, her hourly payrate is $26 per hour
now, she wants to ask for a raise, to make 51880 annually
well, if we check the difference of 51880 and 49696, that'd leave us with the difference in pay, or the raise annual amount
51880 - 49696 = 2184
ok, so she wants $2184 annually more from her work
how much is that in the hours she works annually? well 2184 ÷ ( 28 * 52)
Answer:
the visible number of cubes is 7
Step-by-step explanation:
Assuming that there are no hidden cubes, the # of visible cubes is 7
Answer:
First, a absolute value function is something like:
y = f(x) = IxI
remember how this work:
if x ≥ 0, IxI = x
if x ≤ 0, IxI = -x
Notice that I0I = 0.
And the range of this function is all the possible values of y.
For example for the parent function IxI, the range will be all the positive reals and the zero.
First, if A is the value of the vertex of the absolute function, then we know that A is the maximum or the minimum value of the function.
Now, if the arms of the graph open up, then we know that A is the minimum of the function, and the range will be:
y ≥ A
Or all the real values equal to or larger than A.
if the arms of the graph open downwards, then A is the maximum of the function, and we have that the range is:
y ≤ A
Or "All the real values equal to or smaller than A"
12-8 is 4 and 3/4 is 75% if that is what youre asking but specify
