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10 months ago

How do I multeply Fractions

Mathematics

1 answer:

almond37 [142]10 months ago

4 0

Multiplying simultaneously numerator by numerator and denominator by denominator.

You can multiply fractions, multiplying simultaneously numerator by numerator and denominator by denominator.

2) Notice that whenever possible, we must simplify it to the lowest possible fraction.

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The rate of change (dP/dt), of the number of people on an ocean beach is modeled by a logistic differential equation. The maximu

Kazeer [188]

Answer:

$\frac{dP}{dt} = 2.4P(1 - \frac{P}{1200})$

Step-by-step explanation:

The logistic differential equation is as follows:

$\frac{dP}{dt} = rP(1 - \frac{P}{K})$

In this problem, we have that:

$K = 1200$ , which is the carring capacity of the population, that is, the maximum number of people allowed on the beach.

At 10 A.M., the number of people on the beach is 200 and is increasing at the rate of 400 per hour.

This means that $\frac{dP}{dt} = 400$ when $P = 200$ . With this, we can find r, that is, the growth rate,

$\frac{dP}{dt} = rP(1 - \frac{P}{K})$

$400 = 200r(1 - \frac{200}{1200})$

$166.67r = 400$

$r = 2.4$

So the differential equation is:

$\frac{dP}{dt} = rP(1 - \frac{P}{K})$

$\frac{dP}{dt} = 2.4P(1 - \frac{P}{1200})$

3 0

2 years ago

Find an equation of the tangent to the curve at the given point by both eliminating the parameter and without eliminating the pa

liubo4ka [24]

Im sorry i need points , i am really sorry

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2 years ago

Plz help need answer for angle y

nalin [4]

I got the answer to be 42.

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3 years ago

Somebody please explain this I have a major exam soon and I really need to know how to solve problems like this

nevsk [136]

Answer:

y = 2x - 3

Step-by-step explanation:

Step 1: Find the slope. You find the slope by using the formula y2-y1/x2-x1. (2, 1) and (4, 5) are our points. Let's find our values.

y2= 5

y1= 1

x2 = 4

x1 = 2

Plug in the numbers into the equation. 5 - 1 is 4. 4 - 2 is 2. 4/2 is 2. There. Our slope is 2.

Step 2: Find the b value. Keep in mind that an equation in point-slope form is y = mx + b, where m = the slope, and b = the y-intercept. For this part, you will plug in one of the points as x and y to find the b value. let's use point (4, 5)

The equation then becomes 5 = 2(4) + b. As we know, 2 * 4 is 8. Subtract 8 on both sides of the equation to cancel out the right side and isolate the b variable. 5 - 8 is -3. Even if you use the other point for the equation (1 = 2(2) +b), you should get the same answer of -3.

5 0

2 years ago

This is a question on my partial fractions homework, but no matter what I try I can't figure it out..

Ierofanga [76]

$\dfrac{x^2+x+1}{(x+1)^2(x+2)}=\dfrac{a_1x+a_0}{(x+1)^2}+\dfrac b{x+2}$
$\implies\dfrac{x^2+x+1}{(x+1)^2(x+2)}=\dfrac{(a_1x+a_0)(x+2)+b(x+1)^2}{(x+1)^2(x+2)}$
$\implies x^2+x+1=(a_1+b)x^2+(2a_1+a_0+2b)x+(2a_0+b)$
$\implies\begin{cases}a_1+b=1\\2a_1+a_0+2b=1\\2a_0+b=1\end{cases}\implies a_1=-2,a_0=-1,b=3$

So you have

$\displaystyle\int_0^2\frac{x^2+x+1}{(x+1)^2(x+2)}\,\mathrm dx=-2\int_0^2\frac x{(x+1)^2}\,\mathrm dx-\int_0^2\frac{\mathrm dx}{(x+1)^2}+3\int_0^2\frac{\mathrm dx}{x+2}$
$=\displaystyle-2\int_1^3\dfrac{x-1}{x^2}\,\mathrm dx-\int_0^2\frac{\mathrm dx}{(x+1)^2}+3\int_0^2\frac{\mathrm dx}{x+2}$

where in the first integral we substitute $x\mapsto x+1$ .

$=\displaystyle-2\int_1^3\left(\frac1x-\frac1{x^2}\right)\,\mathrm dx-\frac1{1+x}\bigg|_{x=0}^{x=2}+3\ln|x+2|\bigg|_{x=0}^{x=2}$
$=-2\left(\ln|x|+\dfrac1x\right)\bigg|_{x=1}^{x=3}-\dfrac23+3(\ln4-\ln2)$
$=-2\left(\ln3+\dfrac13-1\right)-\dfrac23+3\ln2$
$=\dfrac23+\ln\dfrac89$

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3 years ago