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3 years ago

Use the zero product property to find the solutions to the equation x^2 + x -30=12

Mathematics

2 answers:

Alla [95]3 years ago

6 0

Answer:

The solutions are x = -7, 6.

Step-by-step explanation:

To find the solutions, move everything to one side of the equation so the equation is equal to 0. Then factor. Set the factors equal to 0 and solve for x.

$x^2 + x - 30 = 12\\x^2 + x -42=0\\(x+7)(x-6) = 0$

x+7 = 0

x = -7

and

x-6 = 0

x = 6

The solutions are x = -7, 6.

Harrizon [31]3 years ago

5 0

Answer:

A on edge:)

Step-by-step explanation:

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poizon [28]

$(2 \times 54 - 2)3 = 108 - 2 \times 3 = 106 \times 3 = 318$

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4 years ago

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Answer:

2x-3+8v

Step-by-step explanation:

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3 years ago

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5. 3x + 5y + 5z =1<br> x - 2y = 5<br> 2x + 4y = 11

lilavasa [31]

Answer:

see explanation

Step-by-step explanation:

Given the 3 equations

3x + 5y + 5z = 1 → (1)

x - 2y = 5 → (2)

2x + 4y = 11 → (3)

Use (2) and (3) to solve for x and y

Multiply (2) by 2

2x - 4y = 10 → (4)

Add (3) and (4) term by term

4x = 21 ( divide both sides by 4 )

x = $\frac{21}{4\\}$

Substitute this value of x into (3)

2 × $\frac{21}{4\\}$ + 4y = 11

$\frac{21}{2\\}$ + 4y = 11 ( subtract $\frac{21}{2\\}$ from both sides )

4y = $\frac{1}{2}$ ( divide both sides by 4 )

y = $\frac{1}{8\\}$

Substitute the values of x and y into (1) and solve for z

3 × $\frac{21}{4\\}$ + 5 × $\frac{1}{8\\}$ + 5z = 1

$\frac{63}{4}$ + $\frac{5}{8}$ + 5z = 1

$\frac{131}{8}$ + 5z = 1 ( subtract $\frac{131}{8}$ from both sides )

5z = - $\frac{123}{8}$ ( divide both sides by 5 )

z = - $\frac{123}{40}$

Solution is

x = $\frac{21}{4\\}$ , y = $\frac{1}{8\\}$ , z = - $\frac{123}{40}$

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3 years ago

Multiply: 12x(x-11)

KengaRu [80]

Answer:

$12x^{2} -132x$

Step-by-step explanation:

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4 years ago

A football is thrown by a quarterback to a receiver. The points in the figure show the height of the football, in feet, above

nevsk [136]

Answer:

Coordinates of the point B will be (14, 3.5).

Step-by-step explanation:

From the graph attached,

Distance between the Quarterback and Receiver = x-coordinate of the point B = 14 yards

Similarly, height of the football from the ground at point B = y-coordinate of the point B = 9 + $\frac{12-9}{2}$

= 9 + 1.5

= 10.5 feet

Since, 1 feet = $\frac{1}{3}$ yards

10.5 feet = $\frac{10.5}{3}$

= 3.5 yards

Therefore, coordinates of the point B will be (14, 3.5).

6 0

4 years ago