Answer:
a[n] = 6n -3
Step-by-step explanation:
The n-th term of an arithmetic sequence with first term a[1] and common difference d can be written as ...
... a[n] = a[1] + (n-1)·d
We can use any of the given terms to find d, and so find the n-th term.
... a[4] = 21 = 3 + (4-1)d
... 18/3 = d = 6 . . . . . subtract 3, divide by 3
So, the n-th term is ...
... a[n] = 3 + (n-1)·6 = 3 + 6n - 6
... a[n] = 6n -3
_____
<u>Check</u>
a[1] = 6·1 - 3 = 3 . . . yes
a[4] = 6·4 -3 = 21 . . . yes
a[10] = 6·10 -3 = 57 . . . yes
Answer:
kikjnknj
Step-by-step explanation:
Answer:
-2 =a
Step-by-step explanation:
6-4(a+2)=8+a
Distribute
6 - 4a - 8 = 8+a
Combine like terms
-2 -4a = 8+a
Add 4a to each side
-2-4a+4a=8+a+4a
-2 = 8+5a
Subtract 8 from each side
-2-8 = 8+5a -8
-10 = 5a
Divide each side by 5
-10/5 = 5a/5
-2 =a
Answer:
The sum of the two smaller sides is supposed to be greater than the third side. According to online, "as long as the sum of any two of those measurements is greater than the third measurement, the three 'sides' will fit together to make a triangle."
Since the smaller sides only add up to the third length this wouldn't be enough to create a triangle. Therefore the final answer is no.
Answer:
a. True
Step-by-step explanation:
Calculus is the mathematical study of continuous change. Calculus is usually developed by working with very small quantities. Calculus has two major branches, which are, differential calculus and integral calculus. Differential calculus involves instantaneous rates of change, and the slopes of curves, while integral calculus deals with the accumulation of quantities, and areas under or between curves.
