Does the source MAC address match your PC interface?

One of the major disadvantages of application service providers (ASPs) is that they:

AVprozaik [17]

Answer:

do not guarantee that applications will fully meet an organization's needs.

Explanation:

An application service provider is a third-party group established to deliver commercial software applications and additional services related to such software and do so online and sometimes their services do not guarantee that their applications will fully meet an organization’s needs.

8 0

2 years ago

The minimum spanning tree of an undirected graph G exists if and only if G is connected. True or False?

zlopas [31]

Answer: True

Explanation:

The definition of minimum spanning tree(MST) says that the graph must be connected and undirected to be considered for MST. It has (V-1) edges where V is the number of vertices. The minimum spanning tree is implemented using Kruskal's algorithm whereby it starts by considering the minimum weighted edge and covers all the edges upto (V-1) edges. So for MST it has to be connected

3 0

2 years ago

What would you have to know about the pivot columns in an augmented matrix in order to know that the linear system is consistent

Scrat [10]

Answer:

The Rouché-Capelli Theorem. This theorem establishes a connection between how a linear system behaves and the ranks of its coefficient matrix (A) and its counterpart the augmented matrix.

$rank(A)=rank\left ( \left [ A|B \right ] \right )\:and\:n=rank(A)$

Then satisfying this theorem the system is consistent and has one single solution.

Explanation:

1) To answer that, you should have to know The Rouché-Capelli Theorem. This theorem establishes a connection between how a linear system behaves and the ranks of its coefficient matrix (A) and its counterpart the augmented matrix.

$rank(A)=rank\left ( \left [ A|B \right ] \right )\:and\:n=rank(A)$

$rank(A)$

Then the system is consistent and has a unique solution.

$\left\{\begin{matrix}x-3y-2z=6 \\ 2x-4y-3z=8 \\ -3x+6y+8z=-5 \end{matrix}\right.$

2) Writing it as Linear system

$A=\begin{pmatrix}1 & -3 &-2 \\ 2& -4 &-3 \\ -3 &6 &8 \end{pmatrix}$ $B=\begin{pmatrix}6\\ 8\\ 5\end{pmatrix}$

$rank(A) =\left(\begin{matrix}7 & 0 & 0 \\0 & 7 & 0 \\0 & 0 & 7\end{matrix}\right)=3$

3) The Rank (A) is 3 found through Gauss elimination

$(A|B)=\begin{pmatrix}1 & -3 &-2 &6 \\ 2& -4 &-3 &8 \\ -3&6 &8 &-5 \end{pmatrix}$

$rank(A|B)=\left(\begin{matrix}1 & -3 & -2 \\0 & 2 & 1 \\0 & 0 & \frac{7}{2}\end{matrix}\right)=3$

4) The rank of (A|B) is also equal to 3, found through Gauss elimination:

So this linear system is consistent and has a unique solution.

8 0

2 years ago

You are asked to write an app to keep track of a relatively small music library. The app should load song information from a dat

gogolik [260]

Answer:

C++ PROGRAM

Explanation:

6 0

2 years ago

What could be one possible reason where the recipient is not guaranteed that the data being streamed will not get interrupted?

IRINA_888 [86]

One possible reason could be low network bandwidth, where the maximum data throughout allowed by the network is insufficient to accommodate the large amount of data being streamed.

Let me know if you have any questions.

3 0

3 years ago