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telo118 [61]
10 months ago
15

4 tons of sand cost $6,240.00. What is the price per pound?

Mathematics
1 answer:
Vsevolod [243]10 months ago
3 0

Answer:$0.78

Step-by-step explanation:

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anastassius [24]

Answer:

$95-$5m

Step-by-step explanation:

after m months the has to pay $5m

so then you just need to subtract 5m from $95

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Can someone please help me on this one
likoan [24]

You know vertical Angles SRU and TRV are congruent.

You are given that Sides UR and VR are congruent.

You are given that Angles SUT and SVT are congruent.

An appropriate choice is the ASA postulate, since you have congruent angles with congruent sides in between.

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3 years ago
Plssss I need help Im in classsss plsss
Sav [38]

Step-by-step explanation:

Y=-4x+3

2x+3y=19

2x+3(-4x+3)=19

2x-12x+9=19

-10x=10

X=-1

y=-4*(-1)+3=4+3=7

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2 years ago
Can anyone help me please
Sauron [17]

Range of values of x is 25°<x<27°.

<u>Step-by-step explanation:</u>

An angle is formed when two rays, a line with one endpoint, meet at one point called a vertex.Alternate interior angles are formed when a transversal passes through two lines. The angles that are formed on opposite sides of the transversal and inside the two lines are alternate interior angles. The Alternate Interior Angles theorem states, if two parallel lines are cut by a transversal, then the pairs of alternate interior angles are congruent.

In above question, sides are equal and so alternate interior angles are equal i.e. 2x + 10° = 62° ⇒ 2x = 52° ⇒ x =26°

∴ range of values of x is 25°<x<27°

4 0
3 years ago
A rocket is launched from a tower. The height of the rocket, y in feet, is related to the
devlian [24]

Answer:

The rocket will reach its maximum height after 6.13 seconds

Step-by-step explanation:

To find the time of the maximum height of the rocket differentiate the equation of the height with respect to the time and then equate the differentiation by 0 to find the time of the maximum height

∵ y is the height of the rocket after launch, x seconds

∵ y = -16x² + 196x + 126

- Differentiate y with respect to x

∴ y' = -16(2)x + 196

∴ y' = -32x + 196

- Equate y' by 0

∴ 0 = -32x + 196

- Add 32x to both sides

∴ 32x = 196

- Divide both sides by 32

∴ x = 6.125 seconds

- Round it to the nearest hundredth

∴ x = 6.13 seconds

∴ The rocket will reach its maximum height after 6.13 seconds

There is another solution you can find the vertex point (h , k) of the graph of the quadratic equation y = ax² + bx + c, where h = -\frac{b}{2a} and k is the value of y at x = h and k is the maximum/minimum value

∵ a = -16 , b = 196

∴ h=-\frac{196}{2(-16)}

∴ h = 6.125

∵ h is the value of x at the maximum height

∴ x = 6.125 seconds

- Round it to the nearest hundredth

∴ x = 6.13 seconds

4 0
3 years ago
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