Answer: i think (4n+1)^2(4n-1)^2 isnt a multiple of 8 for all integers of n because:
(4n + 1)²(4n - 1)²
= [(4n + 1)(4n - 1)]²
= (16n² - 1)²
= 16².n².n² - 2.16.n² + 1
= 8n²(32n² - 4) + 1
can see 8n²(32n² - 4) is a multiple of 8 but 1 isnt a multiple of 8
=> (4n + 1)²(4n - 1)² isnt a multiple of 8 for all integers of n.
Step-by-step explanation:
Answer: look at the picture
Step-by-step explanation: Hope this help :D
Answer:
$100
Step-by-step explanation:
8x= 160
160/8 = 20
x=20
5x = 100
Hi there!
We can find the zeros of a function by solving f(x) = 0. We find the following:

Add 300 to both sides.

Divide by 3.

Take the root and minus root of both sides.

Therefore, the zeros are
x = 10 and x = -10.
~ Hope this helps you!