Ron’s paycheck this week was $17.43 less than last week .His paycheck was 103.76. How much was Ron’s Paycheck ?

Mathematics

1 answer:

True [87]3 years ago

3 0

Answer:

i think 103.76 + 17.43

Step-by-step explanation:

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Which best describes the resulting three-dimensional

Harman [31]

Answer: C

Step-by-step explanation:

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3 years ago

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HELP WHAT'S THE ANSWER PLEASE

Vlad [161]

We can start by eliminating y. Seeing as they already have opposite coefficients, no multiplication or division needs to be done. So, add the two equations together. 3.2x + (-1.6x) = 1.6x. 4.2 + 3.4 = 7.6. 0.5y + (-0.5y) = 0. This leaves us with 1.6x = 7.6. Now divide both sides by 1.6 to get x = 4.75.

Now we can eliminate x. Since the coefficients of x are not opposites, we need to multiply the bottom equation by 2 on both sides. That leaves us with -3.2x - y = 6.8. Now we can add both equations together. 3.2x + (-3.2x) = 0. 0.5y + (-y) = -0.5y. 4.2 + 6.8 = 11. This leaves us with -0.5y = 11. Divide both sides by -0.5 to get y = -22.

Therefore the answer is B: (4.75, -22)

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4 years ago

In circle O below, what is the length of arc AB in radians?

Law Incorporation [45]

Answer:

Length of arc = 0.628 r

Step-by-step explanation:

Given:

∠ AOB = 36°

Radius = (r)

Find:

Length of arc AB = ?

Computation:

$Length\ of \ arc = \frac{\theta}{360}2\pi r\\\\Length\ of \ arc = \frac{36}{360}(2)(\frac{22}{7} ) (r)\\\\Length\ of \ arc =0.628r$

Length of arc = 0.628 r

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3 years ago

7.1 A player throws a fair die and simultaneously flips a fair coin. If the coin lands heads, then she wins twice, and if tails,

Tcecarenko [31]

Answer:

1.875

Step-by-step explanation:

To find the expected winnings, we need to find the probability of all cases possible, multiply each case by the value of the case, and sum all these products.

In the die, we have 6 possible values, each one with a probability of 1/6, and the value of each output is half the value in the die, so we have:

$E_1 = \frac{1}{6}\frac{1}{2} + \frac{1}{6}\frac{2}{2} +\frac{1}{6}\frac{3}{2} +\frac{1}{6}\frac{4}{2} +\frac{1}{6}\frac{5}{2} +\frac{1}{6}\frac{6}{2}$

$E_1 = \frac{1}{12}(1+2+3+4+5+6)$

$E_1 = \frac{21}{12} = \frac{7}{4}$

Now, analyzing the coin, we have heads or tails, each one with 1/2 probability. The value of the heads is 2 wins, and the value of the tails is the expected value of the die we calculated above, so we have:

$E_2 = \frac{1}{2}2 + \frac{1}{2}E_1$