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riadik2000 [5.3K]
2 years ago
3

electronegativity for boron is 2.0, and electronegativity for fluorine is 4.0. which type of bond forms between boron (b) and fl

uorine (f) in bf3?
Chemistry
1 answer:
ddd [48]2 years ago
3 0

Electronegativity for boron is 2.0, and electronegativity for fluorine is 4.0. which type of bond forms between boron (B) and fluorine (F) in BF₃ is non polar covalent bond.

The  BF₃ is the covalent molecule. the electronegativity for boron is 2.0 and the electronegativity for the fluorine is 4.0 . the boron has 3 valence electrons and need 5 more to complete the octet and fluorine has 7 valence electrons . thus boron form three covalent bond with the atom of fluorine and try to complete the octet.

The  BF₃ is a triangular planar molecule. the dipole moment in the  BF₃ molecule is zero therefore  BF₃, boron trifluoride is a non polar covalent molecule.

To learn more about electronegativity here

brainly.com/question/19374222

#SPJ4

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