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neonofarm [45]
2 years ago
9

I NEED HELP ! ANYTHING WILL HELP!

Chemistry
1 answer:
raketka [301]2 years ago
5 0
Trilobites are more common than Sea urchins
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Alchen [17]
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8 0
3 years ago
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The atomic weight of iodine is less than the atomic weight of tellurium. However, Mendeleev listed iodine after tellurium in his
QveST [7]

Explanation :

As we know that Mendeleev arranged the elements in horizontal rows and vertical columns of a table in order of their increasing relative atomic weights.

He placed the elements with similar nature in the same group.

According to the question, the atomic weight of iodine is less than the atomic weight of tellurium. So according to this, iodine should be placed before tellurium in Mendeleev's tables. But Mendeleev placed iodine after tellurium in his original periodic table.

However, iodine has similar chemical properties to chlorine and bromine. So, in order to make iodine queue up with chlorine and bromine in his periodic table, Mendeleev exchanged the positions of iodine and tellurium.

As we know that the positions of iodine and tellurium were reversed in Mendeleev's table because iodine has one naturally occurring isotope that is iodine-127  and tellurium isotopes are tellurium-128 and tellurium-130.

Due to high relative abundance of tellurium isotopes gives tellurium the greater relative atomic mass.

3 0
3 years ago
Draw the structure of a compound of molecular formula C4H8O that has a signal in its 13C NMR spectrum at ≥ 160 ppm. Then draw th
-Dominant- [34]

Answer:

1. Butyraldehyde; 2. but-3-en-1-ol

Explanation:

1. Peak ≥ 160 ppm

The formula C₄H₈O shows that the Index of Hydrogen Deficiency = 1.

It could be caused by either a ring or a double bond.

A peak at ≥ 160 ppm strongly indicates a C=O group, so the rest of the molecule can contain no rings or double bonds.

There are no other heteroatoms, so the compound most be an aldehyde or a ketone.

One compound that meets these criteria is butyraldehyde, CH₃CH₂CH₂CH=O (see Fig. 1.)

2. No rings; all peaks < 160 ppm

If all peaks are < 160 ppm, there can no C=O group.

There is no ring, so there must be a C=C double bond.

There is no other unsaturation, so the O atom must be present as an alcohol or an ether.

One compound that meets these criteria is but-3-en-1-ol, CH₂=CHCH₂CH₂OH (see Fig. 2).

4 0
2 years ago
Why are the Galápagos Islands such a place of interest to the world
DiKsa [7]

Answer:

Explanation:

5 0
2 years ago
Here the answers for what is radiation?
Aleonysh [2.5K]
Transferring heat through electromagnetic waves
5 0
3 years ago
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