Balanced chemical reaction:
MgSO₄(aq) + Sr(NO₃)₂(aq) → Mg(NO₃)₂(aq) + SrSO₄(s).
Ionic reaction:
Mg²⁺(aq) + SO₄²⁻(aq) + Sr²⁺(aq) + 2NO₃⁻(aq) → Mg²⁺(aq) + 2NO₃⁻(aq) + SrSO₄(s).
Net ionic reaction:
Sr²⁺(aq) + SO₄²⁻(aq) → SrSO₄(s).
Magnesium sulfate (MgSO₄), strontium nitrate (Sr(NO₃)₂ and magnesium nitrate (Mg(NO₃)₂) are soluble in water. Strontium sulfate (SrSO₄) is not soluble in water.
This chemical reaction is double displacement reaction - cations and anions of the two reactants switch places and form two new compounds.
The answer is 19.9 grams cadmium.
Assuming there was no heat leaked from the system, the heat q lost by cadmium would be equal to the heat gained by the water:
heat lost by cadmium = heat gained by the water
-qcadmium = qwater
Since q is equal to mcΔT, we can now calculate for the mass m of the cadmium sample:
-qcadmium = qwater
-(mcadmium)(0.850J/g°C)(38.6°C-98.0°C)) = 150.0g(4.18J/g°C)(38.6°C-37.0°C)
mcadmium = 19.9 grams
Mass for carbon = 12
Mass for hydrogen = 1
Mass for oxygen = 16
Mass for nitrogen = 14
12+1+14+16 = 33
165g / 33g = 5
times all the atoms by 5
C5H5O5N5
