To evaluate the combination we proceed as follows:
21C3
Given nCk we shall have:
n!/[(n-k)!k!]
thus plugging the values in the expression we get:
21!/[(21-3)!3!]
=21!/(18!×3!)
=1330
Answer: 1330
The price of this more expensive book was $90.00 ($150 - $60) based on the date acquired from the question above. This problem can be solved using a simple algebra equation which consisted of one variable. The equation is stated as $150 = x + 1.5x (x = $150/2.5 = $60) where x is the price of the cheaper book and 1.5x is the price of the more expensive books because it has 50% higher price than the cheaper book<span>.</span>
Because logarithms were a lot less time-consuming than other methods of finding roots. They were also more accurate in the sense that it was harder to make a mistake.
2+12a. When adding, you're only collecting "like terms".
Answer: 45
Step-by-step explanation: To divide this start with finding how many times 585 goes into 13 which is 0. I put a picture for you to look at.
