Answer:
The expected number of defective batteries to be pulled out is 0.9, which rounded to the nearest integer gives a total of 1, that is, 1 of the 3 batteries is expected to be defective.
Step-by-step explanation:
Given that a box contains 3 defective batteries and 7 good ones, and I reach in and pull out three batteries, to determine what is the expected number of defective batteries, the following calculation must be performed:
3 + 7 = 100
3 = X
10 = 100
3 = X
3 x 100/10 = X
300/10 = X
30 = X
3 x 3/10 = X
0.9 = X
Therefore, the expected number of defective batteries to be pulled out is 0.9, which rounded to the nearest integer gives a total of 1, that is, 1 of the 3 batteries is expected to be defective.
Answer:
3.25 pounds
Step-by-step explanation:
Starting with 25 pounds we trim off 35%:
25 X .35 = 8.75 trimmed off
This leaves 25 - 8.75 pounds of trimmed meat:
25 - 8.75 = 16.25 of trimmed meat.
During cooking we lose another 80% of the weight of the meat:
16.25 X .80 = 13 pounds "cooked off"
So the remaining weight of meat is 16.25 - 13:
16.25 - 13 = 3.25 pounds of trimmed cooked meat.
How sad is that?
To make the second gear aligned with the first it would have to rotate 5 times, a total of 120 seconds and/or 2 minutes will pass
So the answer is I.
Perimeter = 2L + 2W
22m= 2(5) + 2W
22= 10 + 2W
22-10=2W
12= 2W
<h2>
<em><u>Hey</u></em><em><u>!</u></em><em><u>!</u></em><em><u>!</u></em><em><u>!</u></em></h2>
<em><u>Hope</u></em><em><u> </u></em><em><u>this</u></em><em><u> </u></em><em><u>will</u></em><em><u> </u></em><em><u>help</u></em><em><u> </u></em><em><u>u</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em>