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Tresset [83]
2 years ago
6

A ME

Chemistry
1 answer:
Musya8 [376]2 years ago
6 0

The weak base ionization constant, Kb for CN is equal to <u>Kb = [HCN] [OH⁻] / [CN⁻].</u>

While writing the equilibrium expression the pure liquids and solids are taken as unity i.e. 1 so in place of H₂O 1 is taken and the expression is as follows.

Kb = weak base ionization constant

Reaction, CN⁻ + H₂O ⇄ HCN + OH⁻

Kb = \frac{[product  concentration]}{[reactant  concentration]}

Kb = [HCN] [OH⁻] / [CN⁻]

Hence, the weak base ionization constant, Kb = [HCN] [OH⁻] / [CN⁻].

A weak base is a base that ionizes only slightly in an aqueous solution. A base ionization constant (Kb) is the equilibrium constant for the ionization of a base.

Learn more about weak base ionization here:- brainly.com/question/27703015

#SPJ1

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