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3 years ago

Write a definition for each word and use each word in a sentence. crystallization and organic

Chemistry

1 answer:

Artemon [7]3 years ago

3 0

Answer:

Crystallization is the solidification of atoms or molecules into a highly structured form called a crystal.

Explanation:

Organic chemistry is the scientific study of the structure, properties, composition, reactions, and synthesis of organic compounds

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HELP PLEASE!

tia_tia [17]

Vocabulary. Balanced chemical equation: A chemical equation in which the number of each type of atom is equal on the two sides of the equation.

Hope I helped! (´▽`)

__________________________________________________________

単語。平衡化学反応式：各タイプの原子の数が方程式の両側で等しい化学反応式。

私が助けてくれたらいいのに！(´▽`)

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3 years ago

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If it requires 18.2 milliliters of 0.45 molar barium hydroxide to neutralize 38.5 milliliters of nitric acid, solve for the mola

Ghella [55]

Hi! :)

Ba(OH)2 + 2 HNO3 → Ba(NO3)2 + 2 H2O

(18.2 mL) x (0.45 M Ba(OH)2) x (2 mol HNO3 / 1 mol Ba(OH)2) / (38.5 mL HNO3) = 0.43 M HNO3

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3 years ago

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Four cars travel at the same speed down a road. Their mass and kinetic energy are shown in the graph,

Alex777 [14]

Answer:B

Explanation:

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2 years ago

An acid increases the hydroxide ion concentration of water.<br>True<br>or<br>False

ASHA 777 [7]

False is the answer!

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3 years ago

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CO(g)+2H2(g)⇌CH3OH(g)CO(g)+2H2(g)⇌CH3OH(g) This reaction is carried out at a different temperature with initial concentrations o

Katarina [22]

Answer:

9.4

Explanation:

The equation for the reaction can be represented as:

$CO_{(g)}$ + $2H_2O_{(g)}$ ⇄ $CH_3OH_{(g)}$

The ICE table can be represented as:

$CO_{(g)}$ + $2H_2_{(g)}$ ⇄ $CH_3OH_{(g)}$

Initial 0.27 0.49 0.0

Change -x -2x x

Equilibrium 0.27 - x 0.49 -2x x

We can now say that the concentration of $CH_3OH_{(g)}$ at equilibrium is x;

Let's not forget that at equilibrium $CH_3OH_{(g)}$ = 0.11 M

So:

x = [ $CH_3OH_{(g)}$ ] = 0.11 M

[ $CO_{(g)}$ ] = 0.27 - x

[ $CO_{(g)}$ ] = 0.27 - 0.11

[ $CO_{(g)}$ ] = 0.16 M

[ $2H_2_{(g)}$ ] = (0.49 - 2x)

[ $2H_2_{(g)}$ ] = (0.49 - 2(0.11))

[ $2H_2_{(g)}$ ] = 0.49 - 0.22

[ $2H_2_{(g)}$ ] = 0.27 M

$K_C = \frac{[CH_3OH]}{[CO][H_2]^2}$

$K_C = \frac{(0.11)}{(0.16)[(0.27)^2}$

$K_C = 9.4307$

$K_C$ = 9.4

∴ The equilibrium constant at that temperature = 9.4

8 0

3 years ago