The second law states that the acceleration of an object is dependent upon two variables - the net force acting upon the object and the mass of the object. F = ma; a = F/m. This means that Force over the mass. In order to improve the acceleration without redesigning is that the company has to improve the force assuming that the mass is still the same.
Answer:
443 L of carbon dioxide
Explanation:
Combustion reaction: CH₄ (g) + 2O₂ (g) → CO₂(g) + 2H₂O(g)
We assume, that the oxygen is the excess reagent, so let's convert the mass of methane to moles. (mass (g) / molar mass)
Firstly we need to convert the mass from kg to g → 0.300 kg .1000 g / 1kg
300 g / 16 g/mol = 18.75 moles of methane.
Ratio is 1:1, so 18.75 moles of methane will produce 18.75 moles of CO₂
We apply the Ideal Gases Law to find the answer:
Firstly we need to convert the T°C to T°K → 15°C + 273 = 288 K
P . V = n . R. T → V = ( n . R . T ) / P We replace data:
V = (18.75 mol . 0.0821 L.atm/mol.K . 288K) / 1 atm → 442.8 ≅ 443 L
Use the ideal gas law: PV = nRT, and solve for T,
T = PV/nR.
We should convert any of our parameters to units that would be easy to use with a known R value. One option would be to have the pressure in atm, volume in L, and convert the mass of the hydrogen gas to moles:
P = 1.2 atm
V = 750 mL = 0.750 L
n = (0.30 g H2)/(2.0159 g/mol) = 0.1488 mol H2
R = 0.0821 L•atm/mol•K.
Solving for T,
T = (1.2 atm)(0.750 L)/(0.1488 mol H2)(0.0821 L•atm/mol•K) = 73.671 K.
If you opt to leave your temperature in Kelvin, I would go with 74 K, as that has two significant figures like the rest of the values.
If you opt to go with Celsius, then the answer would be a bit awkward if you had to follow two sig figs: 73.671 - 273.15 = -199.49 ≈ -2.0 × 10² °C.
Pick your poison, I suppose.
