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Anna [14]
1 year ago
11

After an overpayment last month, the balance on a customer’s billing statement is −$50.00. This month’s new charges are $124.80.

Mathematics
1 answer:
siniylev [52]1 year ago
3 0

The customer’s current balance after an overpayment last month is D. $174.80.

<h3>How to illustrate the information?</h3>

It should be noted that after an overpayment last month, the balance on a customer’s billing statement is −$50.00 and this month’s new charges are $124.80.

Therefore, the customer’s current balance will be:

= $124.80 - (-$50)

= $124.80 + $50

= $174.80

Learn more about money on:

brainly.com/question/24373500

#SPJ1

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Suppose an airline policy states that all baggage must be box shaped with a sum of​ length, width, and height not exceeding 114
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Answer:

Step-by-step explanation:

Represent the length of one side of the base be s and the height by h.  Then the volume of the box is V = s^2*h; this is to be maximized.

The constraints are as follows:  2s + h = 114 in.  Solving for h, we get 114 - 2s = h.

Substituting 114 - 2s for h in the volume formula, we obtain:

V = s^2*(114 - 2s), or V = 114s^2 - 2s^3, or V = 2*(s^2)(57 - s)

This is to be maximized.  To accomplish this, find the first derivative of this formula for V, set the result equal to 0 and solve for s:

dV

----- = 2[(s^2)(-1) + (57 - s)(2s)] = 0 = 2s^2(-1) + 114s - 2s^2

ds

Simplifying this, we get dV/ds = -4s^2 + 114s = 0.  Then either s = 28.5 or s = 0.

Then the area of the base is 28.5^2 in^2 and the height is 114 - 2(28.5) = 57 in

and the volume is V = s^2(h) = 46,298.25 in^3

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3 years ago
I wanna know why Charli D’amilo is famous. Someone tell me please it’s on a test.
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8 0
3 years ago
Read 2 more answers
a town has a population of 14000 and grows at 4.5% each year. to the nearest tenth of a year how long will it be until the popul
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Answer:

about 6.6 years

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41,500=6,300*x

41,000/6,300=x

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​ Parallelogram ABCD ​ is a rectangle.
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You have $36,948.61 in a brokerage account, and you plan to deposit an additional $3,000 at the end of every future year until y
Luba_88 [7]
Current amount in account
P=36948.61

Future value of this amount after n years at i=11% annual interest
F1=P(1+i)^n
=36948.61(1.11)^n

Future value of $3000 annual deposits after n years at i=11%
F2=A((1+i)^n-1)/i
=3000(1.11^n-1)/0.11

We'd like to have F1+F2=280000, so forming following equation:
F1+F2=280000
=>
36948.61(1.11)^n+3000(1.11^n-1)/0.11=280000

We can solve this by trial and error.


The rule of 72 tells us that money at 11% deposited will double in 72/11=6.5 years, approximately.
The initial amount of 36948.61 will become 4 times as much in 13 years, equal to approximately 147800 by then.
Meanwhile the 3000 a year for 13 years has a total of 39000.  It will only grow about half as fast, namely doubling in about 13 years, or worth 78000.
Future value at 13 years = 147800+78000=225800.
That will take approximately 2 more years, or 225800*1.11^2=278000.

So our first guess is 15 years, and calculate the target amount
=36948.61(1.11)^15+3000(1.11^15-1)/0.11
=280000.01, right on.

So it takes 15.00 years to reach the goal of 280000 years.
8 0
3 years ago
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