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shtirl [24]
3 years ago
14

How many sunflower seeds to get 1000 calories

Mathematics
1 answer:
marysya [2.9K]3 years ago
4 0
Depends on what type if sunflower seeds they are some don't have calories
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Mr. Dixon is ordering pizzas and breadsticks for a school pizza party and has a budget of $76,
sladkih [1.3K]
10x+13y=76 is the awnser
5 0
2 years ago
Solve the triangle A = 2 B = 9 C =8
VARVARA [1.3K]

Answer:

\begin{gathered} A=\text{ 12}\degree \\ B=\text{ 114}\degree \\ C=54\degree \end{gathered}

Step-by-step explanation:

To calculate the angles of the given triangle, we can use the law of cosines:

\begin{gathered} \cos (C)=\frac{a^2+b^2-c^2}{2ab} \\ \cos (A)=\frac{b^2+c^2-a^2}{2bc} \\ \cos (B)=\frac{c^2+a^2-b^2}{2ca} \end{gathered}

Then, given the sides a=2, b=9, and c=8.

\begin{gathered} \cos (A)=\frac{9^2+8^2-2^2}{2\cdot9\cdot8} \\ \cos (A)=\frac{141}{144} \\ A=\cos ^{-1}(\frac{141}{144}) \\ A=11.7 \\ \text{ Rounding to the nearest degree:} \\ A=12º \end{gathered}

For B:

\begin{gathered} \cos (B)=\frac{8^2+2^2-9^2}{2\cdot8\cdot2} \\ \cos (B)=\frac{13}{32} \\ B=\cos ^{-1}(\frac{13}{32}) \\ B=113.9\degree \\ \text{Rounding:} \\ B=114\degree \end{gathered}\begin{gathered} \cos (C)=\frac{2^2+9^2-8^2}{2\cdot2\cdot9} \\ \cos (C)=\frac{21}{36} \\ C=\cos ^{-1}(\frac{21}{36}) \\ C=54.3 \\ \text{Rounding:} \\ C=\text{ 54}\degree \end{gathered}

3 0
1 year ago
What is up guys!
melisa1 [442]

Answer:

  • Yes, No, Yes

Step-by-step explanation:

<u>Use the Pythagorean theorem:</u>

  • a² + b² = c²

<u>Verify this for each line:</u>

1.

  • 28² + 45² = 53²
  • 2809 = 2809
  • Yes

2.

  • 33² + 56² = 64²
  • 4225 ≠ 4096
  • No

3.

  • 36² + 77² = 85²
  • 7225 = 7225
  • Yes
5 0
3 years ago
What is 15 to the third power
Natalka [10]

Answer:

your answer should be 45

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Gabriel wants to paint the model. How
enyata [817]

Answer:

<h2>The area of the base is 144 square inches.</h2><h2>The area of each triangular face is 66 square inches.</h2><h2>Grabiel needs 408 square inches of paint.</h2>

Step-by-step explanation:

The complete problem is attached.

Notice that the figure is a square pyramid, where its base dimensions are 12 inches by 12 inches, which represents an area of

B=12 \times 12 = 144 \ in^{2}

The slant height of the pyramid is 11 inches, which allow us to find the area of each triangle face

A=\frac{1}{2}bh =\frac{1}{2}(12)(11)= 66 \ in^{2}

But there are four triangle faces, so A_{faces} =4(66)=264 \ in^{2}.

Therefore, the area of each triangular face is 66 square inches.

So, the total surface area would be the sum

S=144+264=408 \ in^{2}

Therefore, Gabriel needs 408 square inches to paint the whole model.

4 0
3 years ago
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