Volume of a pyramid = 
Given base is = 140 m
Given height is = 96 m
Volume = 
Hence, volume of pyramid is 4480 m³
1/3 would be greater because
1/3 of 12= 4 while
1/4 of 12 = 3
to check your work you would get a calculator (if possible) and divide 3by 12 or 4 by 12 then if you get .33 (divide 3 by 12 like 3/12) its 1/3. if its .25 (divide 4 by 12 like 4/12) its 1/4
Answer:
Question 1 = c) Medium: 88 ft²
Question 2 = d) 46.7 ft³
Step-by-step explanation:
Question 1
We would be solving this question by finding the surface area of the tent. The shape of the tent is a square based pyramid.
The surface area of a square based pyramid(tent) =
a² + 2ah
Where in the diagram,
a = base length = 4 ft
h = height of the pyramid (tent ) = 9ft
Surface area = 4² + 2 × 4 × 9
= 16 + 72
= 88ft²
Therefore, the size tarp should she purchase is Medium: 88 ft²
Question 2
For question 2, from the attached diagram, we can see that the diagram is a square based pyramid.
To calculate the amount of water that would fill the square based pyramid, we would have to find the Volume of the tent(square based pyramid).
The formula for the Volume of the tent(square based pyramid) = 1/3(a²h)
Where a = base edge
h = height of the pyramid.
From the diagram,
a = base edge => 4ft.
From the question,
h = height of the tent is given as how tall the tent is = 8.75ft.
Therefore, 1/3(a²h)
1/3 × (4ft)²× 8.75ft
= 46.67ft³
Approximately = 46.7ft³
Therefore, the amount of water it would it take to fill the tent, if the tent is 8.75 ft tall is 46.7ft³
Answer:
The answer is D, 80$ for three 1 hour lessons. I hope this helps :D
Answer:
Option D. ![\sqrt[4]{\frac{3x^{2}}{2y}}](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7B%5Cfrac%7B3x%5E%7B2%7D%7D%7B2y%7D%7D)
Step-by-step explanation:
![\sqrt[4]{\frac{24x^{6}y}{128x^{4}y^{5}}}](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7B%5Cfrac%7B24x%5E%7B6%7Dy%7D%7B128x%5E%7B4%7Dy%5E%7B5%7D%7D%7D)
![\sqrt[4]{(\frac{24}{128})\times (\frac{x^{6}}{x^{4}})\times (\frac{y}{y^{5}})}](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7B%28%5Cfrac%7B24%7D%7B128%7D%29%5Ctimes%20%28%5Cfrac%7Bx%5E%7B6%7D%7D%7Bx%5E%7B4%7D%7D%29%5Ctimes%20%28%5Cfrac%7By%7D%7By%5E%7B5%7D%7D%29%7D)
= ![\sqrt[4]{(\frac{3}{16})\times {(x)^{6-4}}\times{(y)^{1-5}}}](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7B%28%5Cfrac%7B3%7D%7B16%7D%29%5Ctimes%20%7B%28x%29%5E%7B6-4%7D%7D%5Ctimes%7B%28y%29%5E%7B1-5%7D%7D%7D)
= ![\sqrt[4]{(\frac{3}{16})\times x^{2}y^{-4}}](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7B%28%5Cfrac%7B3%7D%7B16%7D%29%5Ctimes%20x%5E%7B2%7Dy%5E%7B-4%7D%7D)
= ![\sqrt[4]{\frac{3}{(2)^{4}}\times x\times y^{-4}}](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7B%5Cfrac%7B3%7D%7B%282%29%5E%7B4%7D%7D%5Ctimes%20x%5Ctimes%20y%5E%7B-4%7D%7D)
= ![\sqrt[4]{(3\times x^{2)\times (\frac{y^{-1}}{2})^{4}}}](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7B%283%5Ctimes%20x%5E%7B2%29%5Ctimes%20%28%5Cfrac%7By%5E%7B-1%7D%7D%7B2%7D%29%5E%7B4%7D%7D%7D)
= ![\frac{y^{-1}}{2}\sqrt[4]{3x^{2}}](https://tex.z-dn.net/?f=%5Cfrac%7By%5E%7B-1%7D%7D%7B2%7D%5Csqrt%5B4%5D%7B3x%5E%7B2%7D%7D)
=
Option D. is the correct answer.
