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pychu [463]
2 years ago
8

enuity CUBetween which two numbers will you find 5.634 x 102?OA) 0.0562 and 0.0563OB) 0.0563 and 0.0564OC) 562 and 563OD) 563 an

d 564
Mathematics
1 answer:
Rudiy272 years ago
8 0

The number:

5.634\times10^2

is going to be between the numbers 563 and 564; since 10 squared equals 100 and the decimal point will move to places to the right.

Therefore, the answer is D.

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Suppose James randomly draws a card from a standard deck of 52 cards. He then places it back into the deck and draws a second ca
shutvik [7]

Answer:

0.01923 or 1.92 %

Step-by-step explanation:

The probability of drawing a queen card out of deck is 4/52

∴ P(Q)= 4/52

there are 4 queens in a deck, one of each suit.

The probability of drawing a diamond card out of deck is 13/52

∴P(D)= 13/52

there are 13 cards in diamond suit (including the three face cards).

The total will remain 52 as he has replaced the first card and have not moved it aside

therefore, the net probability for both scenarios will be defined by calculating both probabilities.

P= P(Q) x P(D)

P=  4/52 x 13/52

P=1/52

P=0.01923 (converting into percentage)

P=0.01923  x 100%

P=1.92 %

Answer: the probability that James draws a queen card as the first card and a diamond card as the second card is 1.92%

4 0
3 years ago
2x - 3y = -2
Triss [41]

Answer:

the answer to the question is (6,10)

3 0
4 years ago
Janet deducted $5 on Monday and another $6 on Tuesday from her savings account. How much money did Janet deduct?
emmasim [6.3K]
A total of 5+6 for the total deduction so 11$. Her savings account has a total of -11$ since Monday as another way of phrasing it
7 0
3 years ago
Which of the following is a binomial?
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\boxed{\ }+\boxed{\ } -\ a\ binominal, therefore\ your\ answer\ is:\\\\b.\ c^2-16
5 0
4 years ago
how do you write these equations in slope-intercept form y+1=2x-3 ,2x-3=y+1 , 2y+2=4x-6. Are they the same or different?
inna [77]

y+1=2x-3

y=2x-4

2x-3=y+1

2x-4=y

y=2x-4

2y+2=4x-6

2y=4x-8

y=2x-4

They are all the same: y=2x-4

8 0
4 years ago
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