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erastova [34]
3 years ago
15

Of the 80 house in a development, 50 have a two-car garage, 40 have an in-the-ground swimming pool, and 35 have both a two-car g

arage and an in-the-ground swimming pool. How many houses in the development have neither a two-car garage nor an in-the-ground swimming pool?A. 10B. 15C. 20D. 25E. 30
Mathematics
1 answer:
AVprozaik [17]3 years ago
6 0

Answer:

D. 25

Step-by-step explanation:

See the file attached.

Download pdf
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Hector is opening a bakery. He plans to start by selling cakes. It costs him $4 for each cake, $1.75 per box for the cakes, and
tatiyna

Answer:

D

Step-by-step explanation:

because if you add the numbers up you will get the answer easy :)

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3 years ago
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$265 worth of tickets were sold Adult tickets cost $6 Child tickets cost $2.50 • 57 tickets were sold. How many adult tickets we
BARSIC [14]

Answer:

35 adult tickets were sold

Step-by-step explanation:

If 35 adult tickets were sold, that would be $210

If 22 child tickets were sold, that would be $55

When you add them together, you get 57 tickets and $265.

(I'm sorry I don't know how to explain this but I hope it helped anyway)

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3 years ago
Explain why the Annual Percentage Rate does not compare loans for different lengths of time.
Vika [28.1K]
APR is different than other compounding periods because you would need to find some equivelancy to compare things at.
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3 years ago
A hollow metal sphere has 6 cm inner and 8cm outer radii. The surface charge densities on the exterior surface is +100 nC/m2 and
natulia [17]

Answer:

<h2>Outer Electric Field is 11250 N/C.</h2><h2>Inner Electric Field is -10000 N/C.</h2>

Step-by-step explanation:

First of all, we need to read carefully and analyse the problem. As you can see, is an electrical subject, and it's given surface charge densities and radius.

So, to calculate electric fields, we need to find the proper equation to do so: E=k\frac{q}{r^{2} }; as you can see, first we need to find the charges.

We can find all charges using the surface charge densities, because it has the next relation: p=\frac{q}{A}; which indicates that charge density is the amount of charge per area. But, there's a problem, we don't have areas, so we have to calculate them first with this relation: S=4\pi r^{2}; which gives us the surface of a sphere.

The inner surface: Si=4\pi (0.06m)^{2} = 0.04 m^{2}

The outer surface: S=4\pi (0.08m)^{2}=0.08m^{2}

Now we can calculate the charges,

Inner charge: Qi=pA=(-100\frac{nC}{m^{2} } )(0.04m^{2} )=-4nC

Outer charge: Qo=pA=100\frac{nC}{m^{2} } )(0.08m^{2} )=8nC

Then, we are able to calculate both fields:

Inner field: Ei=k\frac{Qi}{r^{2} }=9x10^{9} \frac{Nm^{2} }{C^{2} }\frac{-4x10^{-9} }{0.06m^{2} }=-10000\frac{N}{C}

Outer field:  Eo=k\frac{Qo}{r^{2} }=9x10^{9} \frac{Nm^{2} }{C^{2} }\frac{8x10^{-9} }{0.08m^{2} }=11250\frac{N}{C}

The directions that field have is opposite each other, the inner one has an inside direction, and the outer electric field has an outside direction.

3 0
3 years ago
Louis borrowed money from his dad to buy a car. After 4 years, Louls finally repaid his dad for the cost of the car and an addit
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