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Shkiper50 [21]
1 year ago
13

Select the expression that represents the simplified difference.

Mathematics
2 answers:
Setler79 [48]1 year ago
8 0

The simplified expression for the given function is 2x + 4 - ( 1 / x-1). The correct option is A.

<h3>What is an expression?</h3>

The mathematical expression combines numerical variables and operations denoted by addition, subtraction, multiplication, and division signs.

Mathematical symbols can be used to represent numbers (constants), variables, operations, functions, brackets, punctuation, and grouping. They can also denote the logical syntax's operation order and other properties.

Given that the functions are f(x) = x + 2 and h(x) = 1 / x-1. The value of the function 2f(x) – h(x) will be calculated as,

E = 2f(x) – h(x)

E =  2( x + 2 ) - ( 1 / x-1)

E = 2x + 4 - (1/x-1)

To know more about an expression follow

brainly.com/question/29008655

#SPJ2

asambeis [7]1 year ago
4 0
<h2>Answer:</h2>

<h2>Step-by-step explanation:</h2>

<h3>1. Write the expressions.</h3>

f(x) = x + 2\\\\h(x) = \frac{1}{x-1}

<h3>2. Write the operation.</h3>

2(x+2)-(\frac{x}{x-1} )

<h3>3. Apply the associative property of multiplication.</h3>

(2)(x)+(2)(2)-(\frac{x}{x-1} )\\ \\2x+4-\frac{x}{x-1}

<h3>4. Express your result.</h3>

2f(x)-h(x)=2x+4-\frac{x}{x-1}

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If f(x) = integral of 1/ (sqrt of t^3 +2)dt, then f'1 = ?
mihalych1998 [28]
Differentiating an integral removes the integral.

f(x) = integral of dt/sqrt(t^3 + 2)
f'(x) = 1/sqrt(x^3 + 2)
f'(1) = 1/sqrt(1^3 + 2)
f'(1) = 1/sqrt(3) = sqrt(3)/3.


I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!
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3 years ago
Find the volume of a prism with base area 32 cm2 and height 1.5 cm.
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How do I solve this: h + 6/5 = 2
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H = 2 - 6/5
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4 0
2 years ago
Which complex number is a distance of sqrt17 from the origin on the complex plane?
lions [1.4K]

Let z=x+iy be a complex number. The distance from this complex number to the origin is

\sqrt{(x-0)^2+(y-0)^2}=\sqrt{x^2+y^2}.

Consider all options:

A. z=2+15i, then \sqrt{2^2+15^2}=\sqrt{229}.

B. z=17+i, then \sqrt{17^2+1^2}=\sqrt{290}.

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Answer: correct choice is D.

4 0
3 years ago
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