Answer:
13.567%
Step-by-step explanation:
We solve the above question, using z score formula
z = (x-μ)/σ, where
x is the raw score = 23.1 ounces
μ is the population mean = 22.0 ounces
σ is the population standard deviation = 1.0 ounce
More than = Greater than with the sign = >
Hence, for x > 23.1 ounces
z = 23.1 - 22.0/1.0
= 1.1
Probability value from Z-Table:
P(x<23.1) = 0.86433
P(x>23.1) = 1 - P(x<23.1)
P(x>23.1) = 1 - 0.86433
P(x>23.1) = 0.13567
Converting to percentage
= 0.13567 × 100
= 13.567%
Therefore, the percentage of regulation basketballs that weigh more than 23.1 ounces is 13.567%
Answer:
4/7
Step-by-step explanation:
Number of Blue vans = 4
Number of white vans = 3
Total number of vans = Number of Blue vans + Number of white vans
= 4 + 3
= 7 vans
Number of blue vans : Number of white vans = 4 : 3
Fraction of vans that are blue = Number of Blue vans / Total number of vans
= 4 / 7
Fraction of vans that are blue = 4/7
If you do the calculations and have in mind the data given then we may say that 1) The company must sell 250 cameras in one day and
2) If the manufacturer increases the production by 50 then the profut would be 400.
Your option is the first one, option A
Answer:
€24
Step-by-step explanation:
We can use ratios to solve this.
3:4 = 18:x
Cross multiply: 3x = 18*4
Divide: x = 18*4/3
Simplify: x = 6*4 = 24