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2 years ago

10

How do you solve this equation on surds?

1 answer:

Arisa [49]2 years ago

6 0

Fist do the parentheses that come first one top then do the second set of parentheses, then add those and you have your answer

You might be interested in

Find the difference:7 7/8-3 1/4=?

Arlecino [84]

Answer:

4 5/8

Step-by-step explanation:

7 7/8 - 3 1/4

7 7/8 - 3 2/8

4 5/8

8 0

3 years ago

For example( and this is straight from the paper), "15 people in 3 equal rows."

densk [106]

At a race, there are 3 rows with 15 people in each row. How many total people are there?

Numerical expression- 15 times 3

(Idk if this helped very much but it's worth a shot)

6 0

3 years ago

I really don’t know how to do this and i could really use some help :) please

Firlakuza [10]

Answer:oh goodness

Step-by-step explanation:

3 0

3 years ago

Below are survival times (in days) of 13 guinea pigs that were injected with a bacterial infection in a medical study:

tresset_1 [31]

Outliers are data that are relatively far from other data elements.

The dataset has an outlier and the outlier is 120

The dataset is given as:

91 83 84 79 91 93 95 97 97 120 101 105 98

Sort the dataset in ascending order

79 83 84 91 91 93 95 97 97 98 101 105 120

<h3>The lower quartile (Q1)</h3>

The Q1 is then calculated as:

$Q1 = \frac{N +1}{4}th$

So, we have:

$Q1 = \frac{13 +1}{4}th$

$Q1 = \frac{14}{4}th$

$Q1 = 3.5th$

This is the average of the 3rd and the 4th element

$Q1 = \frac{1}{2} \times (84 + 91)$

$Q1 = 87.5$

<h3>The upper quartile (Q3)</h3>

The Q3 is then calculated as:

$Q3 = 3 \times \frac{N +1}{4}th$

So, we have:

$Q3 = 3 \times \frac{13 +1}{4}th$

$Q3 = 3 \times 3.5th$

$Q3 = 10.5th$

This is the average of the 10th and the 11th element.

$Q_3 =\frac12 \times (98 + 101)$

$Q_3 =99.5$

<h3>The interquartile range (IQR)</h3>

The IQR is then calculated as:

$IQR = Q_3 -Q_1$

$IQR = 99.5 - 87.5$

$IQR = 12$

Also, we have:

$IQR(1.5) = 12 \times 1.5$

$IQR(1.5) = 18$

<h3>The outlier range</h3>

The lower and the upper outlier range are calculated as follows:

$Lower = Q_1 - IQR(1.5)$

$Lower = 87.5- 18$

$Lower = 69.5$

$Upper = Q_3 + IQR(1.5)$

$Upper = 99.5 + 18$

$Upper = 117.5$

120 is greater than 117.5.

Hence, the dataset has an outlier and the outlier is 120

Read more about outliers at:

brainly.com/question/9933184

6 0

1 year ago

The area of 14 cm wide rectangle is 252 CM what is the length

Olin [163]

Answer: 21cm

Step-by-step explanation:

To find the area of a rectangle you just multiply the length by the width. In this case we have 12(width) x ?(length) = 252. To solve we would just divide the area by the known measurement to find the missing one, so 252/12 =21cm

5 0

2 years ago