Answer:
a
Since the integral has an infinite discontinuity, it is a Type 2 improper integral
b
Since the integral has an infinite interval of integration, it is a Type 1 improper integral
c
Since the integral has an infinite interval of integration, it is a Type 1 improper integral
d
Since the integral has an infinite discontinuity, it is a Type 2 improper integral
Step-by-step explanation:
Considering a

Looking at this we that at x = 3 this integral will be infinitely discontinuous
Considering b

Looking at this integral we see that the interval is between
which means that the integral has an infinite interval of integration , hence it is a Type 1 improper integral
Considering c

Looking at this integral we see that the interval is between
which means that the integral has an infinite interval of integration , hence it is a Type 1 improper integral
Considering d

Looking at the integral we see that at x = 0 cot (0) will be infinity hence the integral has an infinite discontinuity , so it is a Type 2 improper integral
Answer:
A = 325(1.07)^1
Step-by-step explanation:
first one shows an increase of 70%
second one shows a decrease of 7%
Last shows a decrease of 93%
The answer would be A , that’s his slugging percentage ! Hope this helps !
Perimeter can be found by the formula : Perimeter = 2L + 2 W
Perimeter = 2L + 2 W
Perimeter = 2(2a) + 2(a + 1) . ← Option 4
Perimeter = 4a + 2a + 2
Perimeterr = 6a + 2 ← Option 5
Perimeter can also be found by simply adding up all the 4 sides:
Perimeter = L + W + L + W
Perimeter = L + W + L + W
Perimeter = 2a + a + 1 + 2a + a + 1 ← Option 3
Perimeter = 3a + 1 + 3a + 1 ← Option 1
Answer: Option 1, 3, 4 and 5 are correct.