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Leona [35]
3 years ago
5

A school fundraiser sells 1,200 raffel tickets each ticket costs 2 there is one grand prize worth 100 and 5 smaller prizes 20eac

h what is the excpeted gain or loss for buying 1 ticket
Mathematics
1 answer:
UkoKoshka [18]3 years ago
6 0
So you don’t have to click the link from the person before,
the answer is “LOSS OF $1.38” :)
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Help asap grade 5 math help fast help quick !!!
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Answer:

B and D

Step-by-step explanation:

A

\frac{5}{6} × 13 = \frac{5(13)}{6} = \frac{65}{6} = 10 \frac{5}{6} < 13

B

4 × 13 = 52 > 13

C

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7 0
3 years ago
an oil company conducts a geological study that indicates that an exploratory oil well should have a 20% chance of striking oil.
bazaltina [42]

Answer:

4.92% probability that the third strike comes on the seventh well drilled

Step-by-step explanation:

For each drill, there are only two possible outcomes. Either it is a strike, or it is not. Each drill is independent of other drills. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

20% chance of striking oil.

This means that p = 0.2

What is that probability that the third strike comes on the seventh well drilled

2 stikers during the first 6 drills(P(X = 2) when n = 6)[/tex]

Strike during the 7th drill, with 0.2 probability. So

P = 0.2P(X = 2)

In which

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 2) = C_{6,2}.(0.2)^{2}.(0.8)^{4} = 0.2458

Then

P = 0.2P(X = 2) = 0.2*0.2458 = 0.0492

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