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Nutka1998 [239]

11 months ago

13

Samuel and Jason spent 3/4 of their combined earnings from 100 by gift. How much do they spend? Is there enough left over from W

ednesday’s earnings to buy a card that cost $3.25

1 answer:

-Dominant- [34]11 months ago

7 0

They spend $5.88 on a gift, but there is not enough money left over to spend $3.25 on a card, if Samuel and Jason spent 3/4 of their combined earnings from 100 by gift.

<h3>Define equation.</h3>

A formula that expresses the connection between two expressions on each side of a sign is called equation. Typically, it has a single variable and an equal sign. Like this: 2x - 4 Equals 2.

Given,

Samuel and Jason spent 3/4 of their combined earnings from 100 by gift.

Samuel and Jason's profits as of Wednesday are as follows:

Earnings for Samuel:

12.5 x 40

$5.

Earnings for Jason are

7.1 x $0.40

$2.84.

The total revenue for Wednesday is:

Samuel's and Jason's combined incomes are equal.

Earnings totaled

$5 + $2.84 = $7.84

The money that was spent is:

Total income multiplied by 34 equals spent income.

Earnings spent = 7.84 x 1/4

Earnings spent = $5.88

The remainder is:

Equation

Leftover = Total Earnings - Spent Earnings

7.84 - 5.88 = $1.96 in leftovers.

They spend $5.88 on a gift, but there is not enough money left over to spend $3.25 on a card.

To learn more about equation, visit:

brainly.com/question/2420339

#SPJ1

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Increasing and decreasing Functions (anyone help):

Alekssandra [29.7K]

Step-by-step explanation:

the function of increasing for -2.5 < x < 2.5

or written as :

x > -2.5

x < 2.5

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2 years ago

According to government data, 20% of employed women have never been married. If 10 employed women are selected at random, what i

Ierofanga [76]

Answer:

a) $P(X=2) = (10C2) (0.2)^2 (1-0.2)^{10-2}= 0.302$

b) $P(X\leq 2) = P(X=0) + P(X=1) +P(X=2)$

$P(X=0) = (10C0) (0.2)^0 (1-0.2)^{10-0}= 0.107$

$P(X=1) = (10C1) (0.2)^1 (1-0.2)^{10-1}= 0.268$

$P(X=2) = (10C2) (0.2)^2 (1-0.2)^{10-2}= 0.302$

And replacing we got:

$P(X\leq 2) = 0.107+0.268+0.302=0.678$

c) For this case we want this probability:

$P(X\geq 8) = P(X=8) + P(X=9) +P(X=10)$

But for this case the probability of success is p =1-0.2= 0.8

We can find the individual probabilities and we got:

$P(X=8) = (10C8) (0.8)^8 (1-0.8)^{10-8} =0.302$

$P(X=9) = (10C9) (0.8)^9 (1-0.8)^{10-9} =0.268$

$P(X=10) = (10C10) (0.8)^{10} (1-0.8)^{10-10} =0.107$

And replacing we got:

$P(X \geq 8) = 0.677$

And replacing we got:

$P(X\geq 8)=0.0000779$

Step-by-step explanation:

Previous concepts

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

Let X the random variable of interest, on this case we now that:

$X \sim Bin (n=10 ,p=0.2)$

The probability mass function for the Binomial distribution is given as:

$P(X)=(nCx)(p)^x (1-p)^{n-x}$

Where (nCx) means combinatory and it's given by this formula:

$nCx=\frac{n!}{(n-x)! x!}$

Solution to the problem

Let X the random variable "number of women that have never been married" , on this case we now that the distribution of the random variable is:

$X \sim Binom(n=10, p=0.2)$

Part a

We want to find this probability:

$P(X=2)$

And using the probability mass function we got:

$P(X=2) = (10C2) (0.2)^2 (1-0.2)^{10-2}= 0.302$

Part b

For this case we want this probability:

$P(X\leq 2) = P(X=0) + P(X=1) +P(X=2)$

We can find the individual probabilities and we got:

$P(X=0) = (10C0) (0.2)^0 (1-0.2)^{10-0}= 0.107$

$P(X=1) = (10C1) (0.2)^1 (1-0.2)^{10-1}= 0.268$

$P(X=2) = (10C2) (0.2)^2 (1-0.2)^{10-2}= 0.302$

And replacing we got:

$P(X\leq 2) = 0.107+0.268+0.302=0.678$

Part c

For this case we want this probability:

$P(X\geq 8) = P(X=8) + P(X=9) +P(X=10)$

But for this case the probability of success is p =1-0.2= 0.8

We can find the individual probabilities and we got:

$P(X=8) = (10C8) (0.8)^8 (1-0.8)^{10-8} =0.302$

$P(X=9) = (10C9) (0.8)^9 (1-0.8)^{10-9} =0.268$

$P(X=10) = (10C10) (0.8)^{10} (1-0.8)^{10-10} =0.107$

And replacing we got:

$P(X \geq 8) = 0.677$

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3 years ago

You spin each spinner once. You get $50 if you spin a 2 and a vowel. You get $25 if you spin a 2 and a consonant. You get $5 if

Tom [10]

The expected value of the game is $8.75.

----------------------

The expected value is the <u>sum of each outcome multiplied by it's probability</u>.
A probability is the <u>number of desired outcomes divided by the number of total outcomes</u>.

The probability of spinning a 2 and a vowel is: $\frac{1}{4} \times \frac{2}{8} = \frac{2}{32}$ .
Thus, $\frac{2}{32}$ probability of getting $50.

The probability of spinning 2 and a consonant is: $\frac{1}{4} \times \frac{6}{8} = \frac{6}{32}$

Thus, $\frac{6}{32}$ probability of getting $25.

The probability of spinning 1 and a vowel is: $\frac{3}{4} \times \frac{2}{8} = \frac{6}{32}$ .
Thus, $\frac{6}{32}$ probability of getting $5.

32 - (6 + 6 + 2) = 18, thus, $\frac{18}{32}$ probability of earning $0.

The expected value is:

$E = \frac{2}{32}(50) + \frac{6}{32}(25) + \frac{6}{32}(5) + \frac{18}{32}(0)$

$E = \frac{100 + 150 + 30}{32}$

$E = \frac{280}{32}$

$E = 8.75$

The expected value of this game is of $8.75.

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