The complete question is;
The height and diameter of a cone-shaped storage tank are 9 feet and 14 feet respectively. Find the volume of liquid the tank can hold. Round your answer to the integer, if necessary. Use the approximate of value of π, that is 3.14.
Answer:
Volume = 462 ft³
Step-by-step explanation:
We are given;
Height;h = 9 ft
Diameter;d = 14 ft
So, radius;r = 14/2 = 7 ft
Volume of a cone is given by;
V = ⅓πr²h
Where π = 3.14
Thus;
V = ⅓ × 3.14 × 7² × 9
V = 461.58 ft³
Approximating to nearest integer gives; V ≈ 462 ft³
Answer:
C. −0.4, −0.4545454545
Step-by-step explanation:
between −1/2 and −1/3 so it is bet. -0.5 n -0.3333333333333333
only correct ans is C. −0.4, −0.4545454545
Answer:
Solution,
First term (a) = 25
Common difference (d) = Second term - first term = 20 - 25 = -5
Now,
nth term = a + (n - 1)d = 25 + (n - 1) (-5) = 25 - 5n +5 = 30 - 5n
The nth term of the series is 30 - 5n
Answer:
14 units
Step-by-step explanation:
12-(-2)=14
Answer:
The answer to your question is below
Step-by-step explanation:
Question 1
x = 5 Equation l
2x + y = 10 Equation ll
- Substitute Equation l in equation ll
2(5) + y = 10
y = 10 - 10
y = 0
- Solution (5, 0)
Question 2
x + 16y = 20 Equation l
x = 4y Equation ll
Substitute equation ll in equation l
4y + 16y = 20
20y = 20
y = 20/20
y = 1
-Find x
x = 4(1)
x = 4
-Solution
(4, 1)
Question 3
2x + 8y = 20 Equation l
x = 2 Equation ll
-Substitute equation ll in equation l
2(2) + 8y = 20
4 + 8y = 20
8y = 20 - 4
8y = 16
y = 16/8
y = 2
- Solution
(2, 2)
