Answer: I believe it the probability of this would be 1/3.
Step-by-step explanation: This is mainly because if the chances of rolling a 5 or a 4 on a die or fair numbered cube, which contains 6 sides, then landing on 5 or 4 would be 2 out of the six chances it would land on those two numbers. Hope this helps!
Answer:
Let x = the third side
In a triangle, the sum of any 2 sides must be larger than the third side.
I believe this is called the triangle inequality theorem.
We can construct 3 inequalities to obtain the range of values for the third side.
(Inequality #1) 12 + 4 > x
16 > x
(Inequality#2) 12 + x > 4
x > -8 (we can discard this ... we know all sides will be positive)
(Inequality #3) 4 + x > 12
x > 8
So when we combine these together,
8 < x < 16
X (the third side) must be a number between 8 and 16. but not including 8 and 16
Answer:
13 pears in the 21st bag
Step-by-step explanation:
mean = total number of pears/total number of bags
8 = x/21
x = 168
number of pears in 20 bags = (6 x 2) + (7 x 6) + (8 x 9) + (9 x 1) + (10 x 2)
= 155
number of pears in the 21st bag = 168 - 155
= 13
