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mafiozo [28]
3 years ago
8

Plug in a test point to find the region to be shaded

Mathematics
1 answer:
Valentin [98]3 years ago
4 0

is there a picture we can use to understand this?

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What is the least common denominator for the fractions 5/6 and 4/5 ?
laila [671]
C.30 because if u multiply the denominators you get 30 not the other numbers


5 0
3 years ago
Which exponential function is represented by the
Leno4ka [110]

Answer:

C, f(x) = 3(2)^x

Step-by-step explanation:

Since the y-intercept is 3, the function will have 3 multiplying by some number to the power of x.

As x increases by 1, we notice that y multiplies by 2 every time.

This leads us to believe that the equation is 3 * 2^x

8 0
3 years ago
Y<br> 45°<br> 30°<br> N<br> 17<br> I need help pls
melisa1 [442]

Answer:

x=29.4

Step-by-step explanation:

To help find the sides of a triangle, I use SOHCAHTOA.

SOH - CAH - TOA

S=O/H (Sine=\frac{opposite}{hypotenuse} )

C=A/H (Cosine=\frac{adjacent}{hypotenuse} )

T=O/A (Tangent =\frac{opposite}{adjacent} )

Let's find x first. We know 2 parts of the triangle: the adjacent leg, and the angle that is opposite of that.

So it would be tangent (tan).

opposite = 17

adjacent = 30°

Plug these numbers into the calculator and you should get your answer.

\frac{17}{tan(30)} = 29.44486372...

x=29.4

Try to do <em>y</em> on your own and let me know if you have any questions!

Also correct me if I'm wrong on anything.

Hope this information helps!

4 0
3 years ago
Solve for w. 7w=-14<br><br> please help me with this one plz
kolezko [41]

Answer: w = -2

Step-by-step explanation:

7w = -14

Divide both sides by 7

w = -2

That was brief but hope it helps!

5 0
3 years ago
Read 2 more answers
Is the height of an equilateral triangle the same as the sides?
Hoochie [10]
No,
 although all the sides are the same length on an equilateral triangle the height is calculated by a straight perpendicular line at the mid point of the base.

 The sides are not perpendicular with the base and are angled outwards 

7 0
3 years ago
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