Question

Help This is due at the end of class

Answer 1

The coordinates of the vertices of the image of the square are S'(x, y) = (- 1, - 4), T'(x, y) = (- 1, 1), U'(x, y) = (4, 1) and V'(x, y) = (4, - 4).

How to translate a geometric locus set on a Cartesian plane

In this problem we need to make use of a translation on a geometric locus on a Cartesian plane, which is generated by four points representing the vertices of the square. The translation is a kind of rigid transformation, whose formula is shown below:

P'(x, y) = P(x, y) + t(x, y)

Where:

• P(x, y) - Original point
• t(x, y) - Translation vector.
• P'(x, y) - Resulting point

If we know that S(x, y) = (- 6, - 5), T(x, y) = (- 6, 0), U(x, y) = (- 1, 0) and V(x, y) = (- 1, - 5) and t(x, y) = (5, 1), then the locations of the vertices of the triangle are:

S'(x, y) = (- 6, - 5) + (5, 1)

S'(x, y) = (- 1, - 4)

T'(x, y) = (- 6, 0) + (5, 1)

T'(x, y) = (- 1, 1)

U'(x, y) = (- 1, 0) + (5, 1)

U'(x, y) = (4, 1)

V'(x, y) = (- 1, - 5) + (5, 1)

V'(x, y) = (4, - 4)

The location of the image of the square is shown below.

To learn more on translations: brainly.com/question/12463306

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