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Maslowich
3 years ago
7

Can someone help solve number 14 and 15 please

Mathematics
1 answer:
Kryger [21]3 years ago
4 0

Answer:

14: A

15: A

Step-by-step explanation:

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MAKE SURE TO SHOW YOUR WORK (please)
creativ13 [48]

Answer:

9.11 x 10^-28

Step-by-step explanation:

if you divide 9.11 x 10^-28 by 1.67 x 10^-24 you get .000546

if you divide 1.67 x 10^-24 by 9.11 x 10^-28 you get 1,833

therefore, 1.67 x 10^-24 is 1833 times greater than the other value

8 0
3 years ago
Read 2 more answers
Use the Empirical Rule to answer each question.
Oliga [24]

Step-by-step explanation:

(a)

the probability of parcels weighing 35oz or less is

0.841

the probability of parcels weighing 14oz or less is

0.023

the probability of parcels weighing between 14 and 35oz is the probabilty of 35oz minus the probability of 14oz

0.841 - 0.023 = 0.818

the percentage is the probability × 100 = 81.8%

(b)

the probability of parcels weighing more than 49oz is 1 minus the probability to weigh less than 49oz.

the probability to weigh less than 49oz is

0.99865

so, the probability to weigh more than 49oz is

1 - 0.99865 = 0.00135

the percentage is again probability×100 = 0.14%

7 0
3 years ago
Can someone please fill in blank ASAP
Annette [7]

Answer:

The quotient is 48.

Step-by-step explanation:

Estimate the quotient using compatible numbers:

45 (or I guess any number close the answer above, not sure tbh)

Multiply the estimate by 21:

945

45*21

Is the estimate to high or too low?

too low

Adjust and continue until the product is 1008.

1008/21=48

Have a good day/evening! I hope my answer is correct!

8 0
1 year ago
the area of a square poster is 30 in square. Find the length of one side of the poster to the nearest tenth of an inch​
insens350 [35]

Answer:

x = 5.5 (nearest tenth)

Step-by-step explanation:

let x be the length of 1 side

given area of square poster is 30 in²

and

Area = (length of 1 side )²

hence

30 = x²

x = √30

x = 5.4772

x = 5.5 (nearest tenth)

6 0
4 years ago
Please try your best and show your work and I will give brainliest!
dimulka [17.4K]

Answer:

Part A: impossible

Part B: Either equal or blue

Part C: 9 green and 2 blue were added

Step-by-step explanation:

Part A:

The only colors included in this problem are red, blue, and green. There is no black colored pencil, therefore, it is impossible to get one from the box.

Part B:

I'm not sure what you're asking in this question, but I will give you the two choices. If it is before the additional 11 colored pencils are added to the box, the chance of drawing a red and the chance of drawing a blue will be equal, because both of them have 11 of each color. If it is after the additional 11 colored pencils are added to the box, then the chance of drawing a blue colored pencil will be greater than the chance of drawing a red colored pencil. After the 11 colored pencils are added, there are 13 blue and 11 red. The blue is greater.

Part C:

The least number of green colored pencils added has to be 9, because the chance of drawing a green pencil is now greater than the chance of drawing a red pencil. If we add 8 more green pencils, the likelihood would be the same. Therefore, the number of green colored pencils added has to be at least 9. If we have the last 2 colored pencils be blue, then there would be 11 red, 13 blue, and 12 green. This fits all the conditions, therefore, adding 9 green colored pencils and 2 blue colored pencils is the answer.

I hope this helps and please mark me as brainliest!

5 0
2 years ago
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