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Elenna [48]
1 year ago
15

the time, in minutes, it took each of 11 students to complete a puzzle was recorded and is shown in the following list, along wi

th the five-number summary. 9, 17, 20, 21, 27, 29, 30, 31, 32, 35, 58
Mathematics
1 answer:
maw [93]1 year ago
5 0

No, there is only one outlier at 58 minutes.

<h3>What are outliers in data?</h3>

An observation that differs abnormally from other values in a population-based random sample is referred to as an outlier. In a way, this definition defers to the analyst's (or a consensus process') judgment as to what constitutes aberrant behavior. It is vital to define typical observations before distinguishing aberrant ones.

<h3>How do you calculate the outlier?</h3>

A data point is considered an outlier if it is more than 1.5 times the IQR below the first quartile or more than 1.5 times the IQR above the third quartile, according to the general criterion for utilizing it to compute outliers. The first and third quartile percentiles must be known in order to compute the IQR.

<h3>Complete question - </h3>

The time, in minutes, it took each of 11 students to complete a puzzle was recorded and is shown in the following list.

9, 17, 20, 21, 27, 29, 30, 31, 32, 35, 58

One of the students who completed the puzzle claimed that there were two outliers in the data set. Based on the 1.5×IQR rule for outliers, is there evidence to support the student's claim?

To learn more about outliers from given link

brainly.com/question/3631910

#SPJ4

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chubhunter [2.5K]

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AE = 43.2 units

Step-by-step explanation:

As per the given question image, it can be seen that in the \triangle ADC \text { and }\triangle AEB :

1. \angle B = \angle C = 90^\circ

2. \angle A is common to both the triangles.

3. Two angles are common, so the third angle \angle E is also equal to \angle D.

All the three angles in the \triangle ADC \text { and }\triangle AEB are equal to each other, hence the triangles are similar.

As per the property of similar triangles, the ratio of their sides will be equal.

AB : AC = AE : AD

AC = 88 units

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AB = AC - AB = 33 units

Let side AE = x units

Side AD = AE + ED

So, AD = x + 72

Using the ratio:

\dfrac{AB}{AC} = \dfrac{AE}{AD}\\\Rightarrow \dfrac{33}{55} = \dfrac{x}{x+72}\\\Rightarrow 55x = 33 \times 72\\\Rightarrow x = \dfrac{3\times 72}{5}\\\Rightarrow x = 43.2\ units

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8(2w-6)+4(-1-5w)=0

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