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3 years ago

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Mrs. Summers polled the students in her 7th and 8th grade classes to determine the number of pets each student has at home. The

results for both classes are shown in the dot plots below. Calculate the mean and mean absolute deviation of each sample. Then, complete the following question.
The mean number of pets for the 8th grade class is about 1.4 pets____ than the mean number of pets for the 7th grade class. This difference is about____ the mean absolute deviation of either group.

A. higher, lower?
B. same as, twice, half?

2 answers:

Aleonysh [2.5K]3 years ago

8 0

Answer:

B

Step-by-step explanation:

lukranit [14]3 years ago

5 0

The answers is B higher and lower

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<img src="https://tex.z-dn.net/?f=6%5Csqrt%7B3%7D%2B2%281-%5Csqrt%7B27%7D%29%3D2" id="TexFormula1" title="6\sqrt{3}+2(1-\sqrt{27

skelet666 [1.2K]

Answer:

This is true.

Step-by-step explanation:

Step 1: see that √27 is the same as √3*3*3 and thus 3√3

Step 2: remove parenthesis so that 2(1-3√3) becomes 2 - 6√3

Step 3: observe that the equation now becomes 6√3 + 2 - 6√3 = 2

if you simplify any further, you are left with 0=0, which is true.

Comment if there is any step that requires more details...

3 0

3 years ago

Read 2 more answers

A physical trainer decides to collect data to see if people are actually weight changing weight during the shelter in place. He

telo118 [61]

Answer:

H0: µd = 0 (claim)

H1: µd ≠ 0

This is a two-tail t-test for µd

Step-by-step explanation:

This is a paired (dependent) sample test, with its hypothesis is written as :

H0: µd = 0

H1: µd ≠ 0

From the equality sign used in the hypothesis declaration, a not equal to ≠ sign in the alternative hypothesis is used for a two tailed t test

The data isn't attached, however bce the test statistic cannot be obtained. However, the test statistic formular for a paired sample is given as :

T = dbar / (Sd/√n)

dbar = mean of the difference ; Sd = standard deviation of the difference.

3 0

3 years ago

For each vector field f⃗ (x,y,z), compute the curl of f⃗ and, if possible, find a function f(x,y,z) so that f⃗ =∇f. if no such f

butalik [34]

$\vec f(x,y,z)=(2yze^{2xyz}+4z^2\cos(xz^2))\,\vec\imath+2xze^{2xyz}\,\vec\jmath+(2xye^{2xyz}+8xz\cos(xz^2))\,\vec k$

Let

$\vec f=f_1\,\vec\imath+f_2\,\vec\jmath+f_3\,\vec k$

The curl is

$\nabla\cdot\vec f=(\partial_x\,\vec\imath+\partial_y\,\vec\jmath+\partial_z\,\vec k)\times(f_1\,\vec\imath+f_2\,\vec\jmath+f_3\,\vec k)$

where $\partial_\xi$ denotes the partial derivative operator with respect to $\xi$ . Recall that

$\vec\imath\times\vec\jmath=\vec k$

$\vec\jmath\times\vec k=\vec i$

$\vec k\times\vec\imath=\vec\jmath$

and that for any two vectors $\vec a$ and $\vec b$ , $\vec a\times\vec b=-\vec b\times\vec a$ , and $\vec a\times\vec a=\vec0$ .

The cross product reduces to

$\nabla\times\vec f=(\partial_yf_3-\partial_zf_2)\,\vec\imath+(\partial_xf_3-\partial_zf_1)\,\vec\jmath+(\partial_xf_2-\partial_yf_1)\,\vec k$

When you compute the partial derivatives, you'll find that all the components reduce to 0 and

$\nabla\times\vec f=\vec0$

which means $\vec f$ is indeed conservative and we can find $f$ .

Integrate both sides of

$\dfrac{\partial f}{\partial y}=2xze^{2xyz}$

with respect to $y$ and

$\implies f(x,y,z)=e^{2xyz}+g(x,z)$

Differentiate both sides with respect to $x$ and

$\dfrac{\partial f}{\partial x}=\dfrac{\partial(e^{2xyz})}{\partial x}+\dfrac{\partial g}{\partial x}$

$2yze^{2xyz}+4z^2\cos(xz^2)=2yze^{2xyz}+\dfrac{\partial g}{\partial x}$

$4z^2\cos(xz^2)=\dfrac{\partial g}{\partial x}$

$\implies g(x,z)=4\sin(xz^2)+h(z)$

Now

$f(x,y,z)=e^{2xyz}+4\sin(xz^2)+h(z)$

and differentiating with respect to $z$ gives

$\dfrac{\partial f}{\partial z}=\dfrac{\partial(e^{2xyz}+4\sin(xz^2))}{\partial z}+\dfrac{\mathrm dh}{\mathrm dz}$

$2xye^{2xyz}+8xz\cos(xz^2)=2xye^{2xyz}+8xz\cos(xz^2)+\dfrac{\mathrm dh}{\mathrm dz}$

$\dfrac{\mathrm dh}{\mathrm dz}=0$

$\implies h(z)=C$

for some constant $C$ . So

$f(x,y,z)=e^{2xyz}+4\sin(xz^2)+C$

3 0

4 years ago

What is the value of x in the equation 1.5(x + 4) – 3 = 4.5(x – 2)?<br> a 3<br> b 4<br> c 5<br> d 9

Pepsi [2]

The answer would be B) x = 4.

1.5x + 6 - 3 = 4.5x - 9

1.5x + 3 = 4.5x - 9

3 = 4.5x - 9 - 1.5x

3 = 3x - 9

3 + 9 = 3x

12 = 3x

12/3 = x

4 = x

x = 4.

7 0

3 years ago

PLEASE HELP! Will mark brainliest!

OverLord2011 [107]

Been a while since I've done this, but I think I remember what to do here:

The main technique is called "rise over run." The first number, the rise, is how far up the next dot on the right should be. The other number, the run, is how many spaces right the dot should be at. 1+(-2)=-1 and 8+3=11. The next dot on the right should be placed at (11,-1). If you're looking on the left, replace the addition with subtraction. 1-(-2)=3 and 8-3=5. The dot on the left should be (5,3). This means that the three dots on the slope are, in order, (5,3), (1,8), and (11,-1). To find the numbers after the third dot and before the first dot, simply repeat their respective equations.

I hope my memory was correct. Lol

3 0

3 years ago