Answer:
<em>Graph below</em>
Step-by-step explanation:
<u>Transformations</u>
Triangle ABC has coordinates A=(-4,2) B=(-2,6) C=(3,2)
We'll use the transformation (x,y) -> (2x, y+3) to map it to the triangle A'B'C'. Let's calculate the coordinates:
A'=(-8,5)
B'=(-4,9)
C'=(6,5)
The image below shows both triangles in the same grid
Answer:
As a triangle because it's a quadratic shape
Let f(x) = x² + 6x²-x+ 5 then ,
number to be added be P
then,
f(x) = x² + 6x²-x+ 5 +P
According to the qn,
(x+3) is exactly divisible by zero then,
R=0
comparing .. we get a= -3
now by remainder theorm
R=f(a)
0=f(-3)
0=(-3)² + 6(-3)²-(-3)+ 5 + P
0= 9 + 54 + 3 + 5 + P
-71=P
therefore, -71 should be added.
Hope you understand
The minimum of this graph is the focus of the parabola. I'm not sure with the maximum though but I think it doesn't have a maximum because the y value of the parabola will extend infinitely upward.
Answer:
Circumcenter Incenter Centroid
Formed by intersection of Perp. Bisectors Angle bisectors Medians
Type of circle Circumscribed Inscribed No circle
Special property Equidistant from Equidistant from Center of mass
vertices Sides
