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Fofino [41]
2 years ago
13

Find the angle measures of a triangle if the first angle is thirty-one degrees more than the second, and the third is five degre

es less than twice the first. Show the equation as well as the complete answer. (Hint: The sum of the interior angles of a triangle is 180 degrees)
Mathematics
1 answer:
MAVERICK [17]2 years ago
6 0

Answer:

23°, 54°, 103°

Step-by-step explanation:

let the2nd angle = x

1st angle = x + 31

3rd angle = 2(x + 31) - 5 = 2x + 62 - 5 = 2x + 57

Sum the 3 angles and equate to 180

x + 31 + x + 2x + 57 = 180 , that is

4x + 88 = 180 ( subtract 88 from both sides )

4x = 92 ( divide both sides by 4 )

x = 23

Then

1st angle = x + 31 = 23 + 31 = 54°

2nd angle = x = 23°

3rd angle = 2x + 57 = 2(23) + 57 = 46 + 57 = 103°

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zimovet [89]

Answer:他の答えを別の答えに移すことができ、それからミーズビルへの答えを得ることができるとき、それは数学の問題だと自分に言い聞かせてください。

Step-by-step explanation:there

8 0
2 years ago
You have 8,640 grams of a radioactive kind of cesium. If its half-life is 30 years, how much
Vikki [24]

The mass of cesium left afer 120 years if the original mass of cesium is 8640 with an half-life of 30 years,  is 540 grams.

<h3>What is half-life?</h3>

This can be defined as the time taken for half the amount of a radioactive substance to decay.

To calculate the amount of cesium left after 120 years, we use the formua below.

Formula:

  • R' = R/(2^{T/t})............. Equation 1

Where:

  • R = Original amount of Cesium
  • R' = New amount of cesium
  • T = Total time
  • t = Half-life

From the question,

Given:

  • R = 8640
  • T = 120 years
  • t = 30 years

Substitute these values into equation 1

  • R' = 8640/(2^{120/30})
  • R' = 8640/2^{4}
  • R' = 8640/16
  • R' = 540 grams.

Hence, The mass of cesium left afer 120 years is 540 grams.

Learn more about half-life here: brainly.com/question/25750315

4 0
1 year ago
As bases mq e np de um trapézio medem 42 cm e112 cm, respectivamente. se o ângulo mqp é o dobro do ângulo pnm, então o lado pq m
snow_lady [41]

Firstly, we will draw diagram

we will draw line qq'

which will make mqq'n as parallelogram

and we know that opposite sides of parallelograms are always equal

so, we get

mq=nq'

we are given

mq=42

so,

nq'=42

we can see that q' lies on np

so, we can write as

np=nq'+q'p

we are given

np=112

so, we can plug these values

112=42+q'p

q'p=112-42

q'p=70

now, we can see that

triangle qpq' forms isosceles triangle

so, we get

pq=q'p

pq=q'p=70

so,

pq=70............Answer


3 0
2 years ago
(-1.1)^13 x (-1.1)^12 / (-1.1)^10 x (-1.1)^1
olga nikolaevna [1]

Answer:

15.455

Step-by-step explanation:

3 0
3 years ago
I need help with this, I don't understand this
Rudiy27
If you are trying to find the plot you go up as meany numbers as it says and then go over as meany numbers as it says.
8 0
3 years ago
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