The number of ways for which she could pick four colours if green must be one of them is; 10 ways.
<h3>How many ways can she picks four colours if green must be there?</h3>
It follows from the task that there are 6 colours in total that she could pick from.
Hence, since she needs four colours with green being one of them, it follows that she only has 3 colours to pick from 5.
Hence, the numbers of possible combinations is; 5C3 = 10 ways.
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Answer:
15 or -4
Step-by-step explanation:
Answer:
B (6:17)
Step-by-step explanation:
The values of red and white are 8 and 4, so you add them. The ratio should then be 12:34 because 34 is the total of all values. When simplified, 12:34=6:17
Answer:
3/4
Step-by-step explanation:
For an arithmetic sequence, the nth term is the first term plus (n-1)×the differece
the first term is 28, the difference between each adjacent number is 8
so -36=(28)+8(n-1)
8(n-1)=64
n-1=8
n=9
the 9th term is -36
