3/10 × 10 would be 30/100 which would make it easy to add to 21/100 and that would = 51/100
Answer:
percentage applied to pants and sweater is 80%, and that applied to shirt and shoes is 70%
Step-by-step explanation:
<u>Question in English</u>
Leticia and Marta have gone Shopping in the sales. The First has bought $ 42 pants and a $ 24 shirt, and the second has bought a $ 28 sweater and $ 60 shoes. After applying the discounts, Leticia has paid $ 50.4 and Marta $ 64.4. Calculate the percentages of discounts applied knowing that the percentage applied to the pants and the sweater matched and that applied to the shirt and shoes as well.
<u>Solution</u>
Leticia = 42 + 24 = 50.4
Marta = 28 + 60 = 64.4
The percentage applied to the pants and the sweater coincided (that is, it is x) and that applied to the shirt and shoes also (that is, it is y)
Thus,
1) 42x + 24y = 50.4
2) 28x + 60y = 64.4
obtaining and in 1 we have
y = 50.4 - 42x / 24
y = 2.1 - 1.75x
Substituting and in 2 we obtain
28x + 60y = 64.4
28x + 60 (2.1 - 1.75x) = 64.4
28x + 126 - 105x = 64.4
126 - 64.4 = 105x - 28x
x = 61.6 / 77
x = 0.8
Substituting x into 1 gives:
42x + 24y = 50.4
42 (0.8) + 24y = 50.4
33.6 + 24y = 50.4
y = 50.4 -33.6 / 24
y = 0.7
Therefore, the percentage applied to pants and sweater is 80%, and that applied to shirt and shoes is 70%
Answer:
Rate of boat in still water = 70 km/hr
Rate of current = 15 km/hr
Step-by-step explanation:
Let the speed of motorboat in still water =
Let the speed of current =
Equivalent Speed upstream =
Equivalent Speed downstream =
Distance traveled upstream = 440 km
Time taken upstream = 8 hours
Using the formula:
Distance traveled downstream = 510 km
Time taken downstream = 6 hours
Adding (1) and (2):
By equation (1):
Therefore, the answer is:
Rate of boat in still water = 70 km/hr
Rate of current = 15 km/hr
C:65% Would be the answer i believe you're looking for, hope this helps!
X-4/3 <= 5
Multiply both sides by 3:
X-4 <= 15
Add 4 to both sides:
X <= 19
The answer is the third one.