All categories

1 year ago

A semicircle is drawn next to the base of an isosceles triangle such that its diameter is perpendicular to the triangle's

Mathematics

1 answer:

irina1246 [14]1 year ago

7 0

The total area of the semicircle and triangle is 30 + 4.5π .

The diameter of the semicircle is perpendicular to the base of the triangle.

Given diameter length = 6 cm

radius = 6 /2 = 3cm

Area of the semicircle = 1/2 πr² = 1/2π3² = 4.5π

height of the triangle = 10 cm

Area of the triangle = 1/2 × 6 × 10 =30cm

Total area of the figure = 30 + 4.5π

hence the total area of the resulting figure is 30 + 4.5π

A semicircle with one locus of points is referred to as a half-circle in mathematics, more specifically geometry. A semicircle's complete arc is always equal to 180 degrees, radians, or a half-turn.

It only contains one reflectional symmetry line. A half-disk, a twofold geometric entity that includes both the circumferential segment from one end of the arc towards the other and all the inner points, is typically referred to as a "semicircle" in non-technical language.

Disclaimer: The complete question is :

A semicircle is drawn next to the base of an isosceles triangle such that its diameter of 6 cm is perpendicular to the triangle's altitude of 10 cm

To learn more about semicircle visit:

brainly.com/question/29393120

#spj9

You might be interested in

I am the number that is 5,000 greater than the smallest number u can make using six of the digits what number am I?—————————————

Arte-miy333 [17]

12,351,789

ignore this ------

12346789

+ 5000

----------------

12351789

8 0

3 years ago

a daily newspaper has 10225 subscribers when it began publication. six years old later it has 8200 subscribers what is the avera

seraphim [82]

Answer:

The rate of change in number of subscriber for the six years is 3.62%

Step-by-step explanation:

Given as :

The initial subscriber of newspaper = p = 10225

The subscriber of newspaper after 6 years of publish = P = 8200

The time period = t = 6 years

Let The average yearly rate of change = r%

Now, According to question

The subscriber of newspaper after n years = initial subscriber × $(1-\dfrac{\textrm rate}{100})^{\textrm time}$

Or, P = p × $(1-\dfrac{\textrm r}{100})^{\textrm t}$

Or, 8200 = 10225 × $(1-\dfrac{\textrm r}{100})^{\textrm 6}$

Or, $\dfrac{8200}{10225}$ = $(1-\dfrac{\textrm r}{100})^{\textrm 6}$

Or, 0.80195 = $(1-\dfrac{\textrm r}{100})^{\textrm 6}$

Taking power $\dfrac{1}{6}$ both side

So, $(0.80195 )^{\frac{1}{6}}$ = $((1 - \frac{r}{100} )^{6})^{\frac{1}{6}}$

Or, 0.9638 = 1 - $\dfrac{r}{100}$

Or, $\dfrac{r}{100}$ = 1 - 0.9638

Or, $\dfrac{r}{100}$ = 0.0362

Or, r = 0.0362 × 100

i.e r = 3.62

So, The rate of change in subscriber = 3.62%

Hence, The rate of change in number of subscriber for the six years is 3.62% . Answer

4 0

3 years ago

One number is 6 less than 5 times the other number. Their sum is 60. Find the numbers.

OLEGan [10]

Answer:

The numbers are 11 and 49.

Step-by-step explanation:

x = 5y - 6 This is just the first sentence written as an equation.

x + y = 60 This is just the second sentence written as an equation.

5y - 6 + y = 60 Substitute x for what you know it is equal to

6y - 6 = 60 Collect like terms

6y = 66 Add 6 to each side

y = 11 Divide each side by 6

x = 5 × 11 - 6 Substitute y for what you know it is

x = 55 - 6 Simplify by working out 5 × 11 = 55

x = 49 Subtract 6 from 55 to get 49

8 0

2 years ago

Find the missing factor x^2-11x+18=(x-2)( )

tia_tia [17]

I'd use synthetic div. here, with 2 as my divisor:

________________
2 / 1 -11 18
2 -18
----------------------------
1 -9 0

Note that the coefficients of the missing factor are given here and are 1 and -9. Thus, (x-9) is the missing factor.

4 0

3 years ago

I don't know who needs to hear this but I wanted to hopefully reach out to someone.

Alex787 [66]

Answer:

aw thank you sm <3 !!! needed to hear that

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers