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Vesnalui [34]
1 year ago
12

Just need the answer. it was "Check all that apply." at the end.

Mathematics
1 answer:
lianna [129]1 year ago
3 0

Billy, let's recall what a linear pair of angles is:

• They are formed when two lines intersect.

,

• Two angles are said to be linear if they are adjacent angles formed by two intersecting lines.

,

• The measure of a straight angle is 180 degrees, so a linear pair of angles must add up to 180 degrees.

Upon saying that we have that:

• CAD and DAE are linear pairs

,

• CAD and CAB are linear pairs

,

• DAE and BAE are linear pairs

,

• DAE and DAC are linear pairs

Now, you are ready to select all the options that actually apply.

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if gabby wants to make a regular octagon with a side length of 20 inches of water , how much wire does she need?
EleoNora [17]

Answer:

160 inches

Step-by-step explanation:

An octagon has 8 sides;

20*8=160

4 0
3 years ago
*Offering 50 points and brainliest to anyone can explain steps* (Pic attached)
olchik [2.2K]
D because the shaded region has one side and subtract by pie and substitute to get this answer.
7 0
3 years ago
100 POINTS PLS HELP write the value of six dimes as a fracition,with 100 as a demominator
BartSMP [9]

1 dimes are worth 10 cents.

Multiply.

6 * 10 = 60

Put in a fraction with the denominator given.

60/100

Reduce the fraction.

60/100

30/50

15/25

3/5

Best of Luck!

7 0
3 years ago
Read 2 more answers
A rectangular prism has a length of 5/2 ft, width of 9/6 ft, and height of 2/3 ft. what is its volume?
ivanzaharov [21]
The formula of the volume of the rectangular prism:

V = length × width × height

We have:
l=\dfrac{5}{2}ft\\\\w=\dfrac{9}{6}ft\\\\h=\dfrac{2}{3}ft\\\\V=l\cdot w\cdot h=\dfrac{5}{2}\cdot\dfrac{9}{6}\cdot\dfrac{2}{3}\\\\=\dfrac{5}{2}\cdot\dfrac{1}{1}\cdot\dfrac{1}{1}=\dfrac{5}{2}=2.5ft.^3
6 0
3 years ago
The overhead reach distances of adult females are normally distributed with a mean of 205 cm and a standard deviation of 7.8 cm.
devlian [24]

Answer:

Given the mean = 205 cm and standard deviation as 7.8cm

a. To calculate the probability that an individual distance is greater than 218.4 cm, we subtract the probability of the distance given (i.e 218.4 cm) from the mean (i.e 205 cm) divided by the standard deviation (i.e 7.8cm) from 1. Therefore, we have 1- P(Z\leq 1.72). Using the Z distribution table we have 1-0.9573. Therefore P(X >218.4)= 0.0427.

b. To calculate the probability that mean of 15 (i.e n=15) randomly selected distances is greater than 202.8, we subtract the probability of the distance given (i.e 202.8cm) from the mean (i.e 205 cm) divided by the standard deviation (i.e 7.8cm) divided by the square root of mean (i.e n= 15)  from 1. Therefore, we have 1- P(Z\leq -1.09). Using the Z distribution table we have 1-0.1378. Therefore P(X >202.8)= 0.8622.

c. This will also apply to a normally distributed data even if it is not up to the sample size of 30 since the sample distribution is not a skewed one.

Step-by-step explanation:

Given the mean = 205 cm and standard deviation as 7.8cm

a. To calculate the probability that an individual distance is greater than 218.4 cm, we subtract the probability of the distance given (i.e 218.4 cm) from the mean (i.e 205 cm) divided by the standard deviation (i.e 7.8cm) from 1. Therefore, we have 1- P(Z\leq 1.72). Using the Z distribution table we have 1-0.9573. Therefore P(X >218.4)= 0.0427.

b. To calculate the probability that mean of 15 (i.e n=15) randomly selected distances is greater than 202.8, we subtract the probability of the distance given (i.e 202.8cm) from the mean (i.e 205 cm) divided by the standard deviation (i.e 7.8cm) divided by the square root of mean (i.e n= 15)  from 1. Therefore, we have 1- P(Z\leq -1.09). Using the Z distribution table we have 1-0.1378. Therefore P(X >202.8)= 0.8622.

c. This will also apply to a normally distributed data even if it is not up to the sample size of 30 since the sample distribution is not a skewed one.

4 0
3 years ago
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