Answer: 99.51%
Step-by-step explanation:
Given : A survey found that women's heights are normally distributed.
Population mean : 
Standard deviation: 
Minimum height = 4ft. 9 in.=
Maximum height = 6ft. 2 in.=
Let x be the random variable that represent the women's height.
z-score : 
For x=57, we have
For x=74, we have
Now, by using the standard normal distribution table, we have
The probability of women meeting the height requirement :-
Hence, the percentage of women meeting the height requirement = 99.51%
A, because
rectangle- at least 1 angle should be 90 degrees.
square- all angles and sides should have the same measures.
quadrilateral- its any shape with 4 sides.
parallelogram-both pairs of opposite sides parallel and congruent.
rhombus-diagonals are perpendicular which means the angle of the perpendicular lines would be 90 degrees.
Plz help ,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,
Deffense [45]
Hi I figured it out for you all you need to do is plug in the X factor .number 3 is y=-1
Answer:
P(3) is true since 2(3) - 1 = 5 < 3! = 6.
Step-by-step explanation:
Let P(n) be the proposition that 2n-1 ≤ n!. for n ≥ 3
Basis: P(3) is true since 2(3) - 1 = 5 < 3! = 6.
Inductive Step: Assume P(k) holds, i.e., 2k - 1 ≤ k! for an arbitrary integer k ≥ 3. To show that P(k + 1) holds:
2(k+1) - 1 = 2k + 2 - 1
≤ 2 + k! (by the inductive hypothesis)
= (k + 1)! Therefore,2n-1 ≤ n! holds, for every integer n ≥ 3.
Answer:
answer is A
Step-by-step explanation:
