Question

3. Ms. Turner's garden has side lengths of V17 yards and V24 yards.

Answer 1

Answer:

Mr. Webster's garden is greater than Ms. Turner's garden by 282 sq. yards.

Step-by-step explanation:

Representing the length of the garden by l and width of the garden by w.

For turner's garden, given that l= 24 yards and w= 17 yards.

As the area, A, of the rectangular garden having  length l and width w is

So, the area of Ms. Turner's garden, = 24x17=408 sq. yards

For turner's garden, given that l= 5 yards and w= 138 yards.

So, by using equation (i),

the area of Mr. Webster's garden, = 5x138=690 sq. yards

Here, $A_2 > A_1$, and  

= 690-408= 282 sq. yards.

Hence, Mr. Webster's garden is greater than Ms. Turner's garden by 282 sq. yards.