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1 year ago

What is the measure of m<1 will ensure that the rail is parallel to the bottom of the staircase?

Mathematics

1 answer:

cricket20 [7]1 year ago

6 0

You can observe that angle 1 and angle with 47° are inside a parallelogram.

Consider that the sum of the internal angles of a parallelogram is 360°.

Moreover, consider that the angle at the top right of the parallogram is congruent with the angle of 47°, then, such an angle is if 47°.

Consider that angle down right side is congruent with angle 1, then, they have the same measure.

You can write the previous situation in the following equation:

47 + 47 + ∠1 + ∠1 = 360 simplify like terms

94 + 2∠1 = 360 subtract both sides by 94

2∠1 = 360 - 94

2∠1 = 266 divide by 2 both sides

∠1 = 266/2

∠1 = 133

Hence, the measure of angle 1 is m∠1 = 133°

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A 500-gallon tank initially contains 220 gallons of pure distilled water. Brine containing 5 pounds of salt per gallon flows int

Wittaler [7]

Answer: The amount of salt in the tank after 8 minutes is 36.52 pounds.

Step-by-step explanation:

Salt in the tank is modelled by the Principle of Mass Conservation, which states:

(Salt mass rate per unit time to the tank) - (Salt mass per unit time from the tank) = (Salt accumulation rate of the tank)

Flow is measured as the product of salt concentration and flow. A well stirred mixture means that salt concentrations within tank and in the output mass flow are the same. Inflow salt concentration remains constant. Hence:

$c_{0} \cdot f_{in} - c(t) \cdot f_{out} = \frac{d(V_{tank}(t) \cdot c(t))}{dt}$

By expanding the previous equation:

$c_{0} \cdot f_{in} - c(t) \cdot f_{out} = V_{tank}(t) \cdot \frac{dc(t)}{dt} + \frac{dV_{tank}(t)}{dt} \cdot c(t)$

The tank capacity and capacity rate of change given in gallons and gallons per minute are, respectivelly:

$V_{tank} = 220\\\frac{dV_{tank}(t)}{dt} = 0$

Since there is no accumulation within the tank, expression is simplified to this:

$c_{0} \cdot f_{in} - c(t) \cdot f_{out} = V_{tank}(t) \cdot \frac{dc(t)}{dt}$

By rearranging the expression, it is noticed the presence of a First-Order Non-Homogeneous Linear Ordinary Differential Equation:

$V_{tank} \cdot \frac{dc(t)}{dt} + f_{out} \cdot c(t) = c_0 \cdot f_{in}$ , where $c(0) = 0 \frac{pounds}{gallon}$ .

$\frac{dc(t)}{dt} + \frac{f_{out}}{V_{tank}} \cdot c(t) = \frac{c_0}{V_{tank}} \cdot f_{in}$

The solution of this equation is:

$c(t) = \frac{c_{0}}{f_{out}} \cdot ({1-e^{-\frac{f_{out}}{V_{tank}}\cdot t }})$

The salt concentration after 8 minutes is:

$c(8) = 0.166 \frac{pounds}{gallon}$

The instantaneous amount of salt in the tank is:

$m_{salt} = (0.166 \frac{pounds}{gallon}) \cdot (220 gallons)\\m_{salt} = 36.52 pounds$

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3 years ago

15a2-6ab-8a2 - 5ab + 20+ a? - ab - 31 -

Crazy boy [7]

-12ab+7a power of 2 +a 11

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3 years ago

What is the quotient of 35, 520 ÷ 96?

Verdich [7]

Answer:

Hey there the answer is 370

Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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3 years ago

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aleksandrvk [35]

Answer:

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Step-by-step explanation:

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hope this helped!

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3 years ago